Answer:
![\sqrt[n]{x}=x^{\frac{1}{n}}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Bx%7D%3Dx%5E%7B%5Cfrac%7B1%7D%7Bn%7D%7D)
Step-by-step explanation:
The index of a radical is the denominator of a fractional exponent, and vice versa. If you think about the rules of exponents, you know this must be so.
For example, consider the cube root:
![\sqrt[3]{x}\cdot \sqrt[3]{x}\cdot \sqrt[3]{x}=(\sqrt[3]{x})^3=x\\\\(x^{\frac{1}{3}})^3=x^{\frac{3}{3}}=x^1=x](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%7D%5Ccdot%20%5Csqrt%5B3%5D%7Bx%7D%5Ccdot%20%5Csqrt%5B3%5D%7Bx%7D%3D%28%5Csqrt%5B3%5D%7Bx%7D%29%5E3%3Dx%5C%5C%5C%5C%28x%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D%29%5E3%3Dx%5E%7B%5Cfrac%7B3%7D%7B3%7D%7D%3Dx%5E1%3Dx)
That is ...
![\sqrt[3]{x}=x^{\frac{1}{3}} \quad\text{radical index = fraction denominator}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%7D%3Dx%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D%20%5Cquad%5Ctext%7Bradical%20index%20%3D%20fraction%20denominator%7D)
As you progress in math, it will become increasingly important that you know how to express exponentiation properly.
y = 2x3 – x2 – 4x + 5 should be written <span>y = 2^x3 – x^2 – 4^x + 5. The
" ^ " symbol denotes exponentiation.
I see you're apparently in middle school. Is that so? If so, are you taking calculus already? If so, nice!
Case 1: You do not yet know calculus and have not differentiated or found critical values. Sketch the function </span>y = 2x^3 – x^2 – 4^x + 5, including the y-intercept at (0,5). Can you identify the intervals on which the graph appears to be increasing and those on which it appears to be decreasing?
Case 2: You do know differentiation, critical values and the first derivative test. Differentiate y = 2x^3 – x^2 – 4^x + 5 and set the derivative = to 0:
dy/dx = 6x^2 - 2x - 4 = 0. Reduce this by dividing all terms by 2:
dy/dx = 3x^2 - x - 2 = 0 I used synthetic div. to determine that one root is x = 2/3. Try it yourself. This leaves the coefficients of the other factor, (3x+3); this other factor is x = 3/(-3) = -1. Again, you should check this.
Now we have 2 roots: -1 and 2/3
Draw a number line. Locate the origin (0,0). Plot the points (-1, 0) and (2/3, 0). This subdivides the number line into 3 subintervals:
(-infinity, -1), (-1, 2/3) and (2/3, infinity).
Choose a test number from each interval and subst. it for x in the derivative formula above. If the derivative comes out +, the function is increasing on that interval; if -, the function is decreasing.
Ask all the questions you want, if this explanation is not sufficiently clear.
Answer:
243789
Step-by-step explanation:
(34827) 7 = 243789
Hope this helps!
It is given that, B ≅ BC and AD ≅ CD
We need BD perpendicular to AC, then only we can say triangles AXB and CXB are congruent using the HL theorem.
If BD perpendicular to AC, means that AB and CB are the hypotenuse of triangles AXB and CXB respectively.
from the given information ABCD is a square
If BD and AC bisect each other then AX = CX
Then only we can immediately possible to prove that triangles AXD and CXD are congruent by SSS congruence theorem
