Question

A ball made out of a special material is inflated such that its diameter changes from 14 inches to 18 inches. What is the approximate change in the volume of the ball?

Answer 1

The volume of the ball is:
 V = (4/3) * (pi) * (r ^ 3)
 Where r is the radius.
 We have then:
 diameter 14 inches:
 V1 = (4/3) * (pi) * ((14/2) ^ 3)
 V1 = 1436.75504 in ^ 3
 diameter 18 inches:
 V2 = (4/3) * (pi) * ((18/2) ^ 3)
 V2 = 3053.628059 in ^ 3
 The volume change is:
 V = V2-V1
 V = 3053.628059 - 1436.75504
 V = 1616.873019 in ^ 3
 Answer:
 The approximate change in the volume of the ball is:
 V = 1616.9 in ^ 3