That will be c) the third one
<span>Answer: T-cells are made to identify antigens, while inflammation fights anything in the affected area
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The adaptive immune cells are made of B-cell and T-cell. The function of B-cells is to produce antibodies, while T-cells will detect antigens of the pathogen. If T-cells detect an antigen from a cell, it will assume that the cells are infected. It will send a signal to the infected cells which tell them to do apoptosis. Inflammation is not specific, which makes them not strong.
O positive is the most common blood type and most likely to be transfused.
O negative donors are the “Universal Donor.” People with O negative blood are universal red blood cell donors. This means that their red blood cells can be transfused to any blood type.
Answer:
See the answer below
Explanation:
<em>Recall that the law of dilution states that the number of moles before dilution must be equal to the number of moles after dilution.</em>
Mathematically,
molarity x number of moles before dilution = molarity x number of moles after dilution.
For solution A: final molarity = 3 mM, final volume = 2mL, initial molarity of KMnO4 = 10 mM
Applying the equation:
10 x initial volume = 3 x 2
initial volume = 6/10 = 0.6
<u>Hence, Tube A should be made with 0.6 mL of 10 mM KMnO4 stock and 1.4 mL of distilled water to give a solution of 2 mL 3 mM KMnO4.</u>
For solution B:final molarity = 8 mM, final volume = 2 mL, initial molarity = 10 mM
10 x initial volume = 8 x 2
initial volume = 16/10 = 1.6
<u>Hence, Tube B should be made with 1.6 mL of 10 mM KMnO4 stock and 0.4 mL of distilled water to give a solution of 2 mL 8mM KMnO4. </u>
Answer:
The correct answer is option C (voltage gated Na+ channels).
Explanation:
Output region or axon terminal is the structure of neuron which transmits the signals to other nerve cells.
The signal is transferred via action potential generated by the dendrite cell which moves along the axon and reaches the synaptic junction.
At the synaptic junction, voltage-gated channel (Na+) channels located in the membrane of the axon terminal cell opens due to the changes in the electric membrane potential which play important role in returning the depolarized cell to a resting state.
Thus, option C (voltage-gated Na+ channels) is the correct answer.
