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3 years ago

Please help with these 2 !! Thank you

Mathematics

1 answer:

MatroZZZ [7]3 years ago

3 0

Because we have been given the slope and y-intercept, we can create an equation in slope-intercept form.

y = mx + b

m = the slope

b = y-intercept.

In the first problem,

m = -4

b = 10

So, our equation looks like: y = -4x + 10

In the second problem,

m = 1/3

b = -6

So, our equation looks like: y = 1/3x - 6

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I don’t understand this problem can someone explain it and give the answe

Feliz [49]

Answer:

Explanation:

4x + 2x = 180 degree
6x = 180
x = 180/6
x = 30

Therefore, x = 30 degree

6 0

3 years ago

PLEASE HELP:))))))) 15points

Zielflug [23.3K]

Answer:7 cm

Step-by-step explanation: you know everything except the radius. Use this equation to help you: 44=2*pi*radius

Divide 44 by 2pi. Then u have your radius which is 7

7 0

3 years ago

The three angles in a triangle are in the ratio 3:5:7. Find the largest angle in the triangle?

Rzqust [24]

Answer: The largest angle is 7x

Step-by-step explanation:

Their sum is 180, so

3x + 5x + 7x = 180

5x = 180 --> x = 12

The largest angle is 7x, which is 7(12) = 84

7 0

3 years ago

Please help very urgent

Alik [6]

Answer:

32, 16, 8, 4, 2, 1

Explanation:

The geometric mean can be represented by $\sqrt[n]{x_{1} • x_{2} • x_{3} • .. x_{n}}$ .

Which is the mean of the product of n numbers, used to find the average of a geometric progression.

Don't get confused by geometric mean, it is only asking you about the next numbers in the geometric sequence given the first and sixth term.

The explicit rule for a geometric sequence can be modeled by:

$a_{n} = a_{1} • r^{n-1}$

Where $a_{n}$ is the nth term, $a_{1}$ is the first term in the sequence, n is the term number, and r is the common ratio.

Since we already know the first term, $a_{1}$ will simply be 32.

Since we know it's geometric, there will be an exponential relationship, which means that we will use the geometric mean to find the common ratio.

There are 6 total terms, r is raised to the n – 1 so 6 – 1 = 5, and that will be the degree of this root.

$\sqrt[5]{\frac{a_{6}}{a_{1}}}$ =

$\sqrt[5]{\frac{1}{32}}$ =

$\frac{1}{2}$ .

Therefore: $r = \frac{1}{2}$ .

Using all the information we have, we can find the explicit rule:

$a_{n} = a_{1} • r^{n-1}$

$a_{1}$ = 32
$r = \frac{1}{2}$

$a_{n} = a_{1} • r^{n-1}$ →

$\boxed{a_{n} = 32 • (\frac{1}{2})^{n-1}}$

________________________________

We can test that this works by substituting the number location of the term you want to find.

For instance:

$a_{1} = 32 • (\frac{1}{2})^{1-1}$

$a_{1} = 32 • (\frac{1}{2})^{0}$

$a_{1} = 32 • 1$

$a_{1} = 32$

$a_{6} = 32 • (\frac{1}{2})^{6-1}$

$a_{6} = 32 • (\frac{1}{2})^{5}$

$a_{6} = 32 • \frac{1}{32}$

$a_{6} = 1$

3 0

3 years ago

Read 2 more answers

Help please! I already know the answer isn't -2, -1 so I need help figuring out the rest!

Lelu [443]

the function is increasing from x = 0 to x = 1

when x = 0, y = 2

when x = 1, y = 8

this shows an increase of +6, so we know this statement is true

we can see the rest are false simply because they state a decrease when there is an increase. this question is only confusing because we ask you about the increase and decrease in the function, when really its the same thing as asking about an increase or decrease in the y variable.

in other words, all youre looking for is the variation of the value of the y variable that is attached to the specific x variables.

hope this helps!!

8 0

2 years ago