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kow [346]
3 years ago
7

What is cyber crime ? easy definition​

Computers and Technology
1 answer:
Naddika [18.5K]3 years ago
4 0

Answer:

Cyber crime is defined as a crime in which a computer is the object of the crime (hacking, phishing, spamming) or is used as a tool to commit an offense .

Explanation:

You might be interested in
In your own words, describe the structure and function of both the stack and queue data structure and discuss how they are diffe
Kobotan [32]

Answer:

Following are the answer to this question:

Explanation:

Stack:

The stack data structure is used to create method, parsing, analysis of expression, and tracking. This data type uses the LIFO system, which stands from the Last In First Out. This data structure operates on the top side. In this data structure, it performs two methods, that are "push() and pop()" method and the time complexity of the stack data structure O(1).

Example of Stack:

import java.util.*;//import package

 public class Main //defining class Main

{      

public static void main (String[] ag)//defining main method  

  {

     ArrayDeque<Character> stack = new ArrayDeque<Character>();//creating Character array ArrayDeque  

       stack.push('A'); //add value in stack  

      stack.push('B');//add value in stack  

      stack.push('B'); //add value in stack  

      System.out.println("First Insert:"+stack); //print value         stack.pop();//remove value from stack    

    System.out.println("After removing element: "+stack); //print value         stack.push('B'); //add value in stack    

    stack.pop();//remove value from stack      

 System.out.println("final value: "+stack); //print value    

}

}

Output:

First Insert:[B, B, A]

After removing element: [B, A]

final value: [B, A]

Queue:

The queue data structure is an abstract type, it is similar to the stacks data structure. It is open at both ends when opposed to lines. It follows the FIFO method, which stands for the First-In-First-Out method, At one end data is inserted and at the other end, it deletes the data and the time complexity of the queue data structure O(1).

Example of Queue:

import java.util.*;//import package  

public class Main//defining a class queue

{  

    public static void main(String[] ars)//defining main method

    {  

      LinkedList<Integer> que= new LinkedList<Integer>();//defining integer array LinkedList    

      for (int i = 0; i < 5; i++)//defining fo loop to add value in queue  

     {    

        que.add(i); //use add method to insert value        

}        

System.out.println("Queue value: "+ que); //print queue value      

  int remove= que.remove(); //remove value from the queue          System.out.println("after removing value from queue: "+ remove);//removing element from queue  

      System.out.println(que);  //after removing the element print value  

  }

}  

Output:

Queue value: [0, 1, 2, 3, 4]

after removing value from queue: 0

[1, 2, 3, 4]

6 0
3 years ago
C++
daser333 [38]

#include<iostream>

#include <fstream>

#include <vector>

#include <string>

#include "StatePair.h"

using namespace std;

int main() {

ifstream inFS;

int zip;

int population;

string abbrev;

string state;

unsigned int i;

vector<StatePair <int, string>> zipCodeState;

vector<StatePair<string, string>> abbrevState;

vector<StatePair<string, int>> statePopulation;

inFS.open("zip_code_state.txt");

if (!inFS.is_open()) {

    cout << "Could not open file zip_code_state.txt." << endl;

    return 1;

}

while (!inFS.eof()) {

    StatePair <int, string> temp;

    inFS >> zip;

    if (!inFS.fail()) {

        temp.SetKey(zip);

    }

    inFS >> abbrev;

    if (!inFS.fail()) {

        temp.SetValue(abbrev);

    }

    zipCodeState.push_back(temp);

}

inFS.close();

inFS.open("abbreviation_state.txt");

if (!inFS.is_open()) {

    cout << "Could not open file abbreviation_state.txt." << endl;

    return 1;

}

while (!inFS.eof()) {

    StatePair <string, string> temp;

    inFS >> abbrev;

    if (!inFS.fail()) {

        temp.SetKey(abbrev);

    }

    getline(inFS, state);

    getline(inFS, state);

    state = state.substr(0, state.size()-1);

    if (!inFS.fail()) {

        temp.SetValue(state);

    }

    abbrevState.push_back(temp);

}

inFS.close();

inFS.open("state_population.txt");

if (!inFS.is_open()) {

    cout << "Could not open file state_population.txt." << endl;

    return 1;

}

while (!inFS.eof()) {

    StatePair <string, int> temp;

    getline(inFS, state);

    state = state.substr(0, state.size()-1);

    if (!inFS.fail()) {

        temp.SetKey(state);

    }

    inFS >> population;

    if (!inFS.fail()) {

        temp.SetValue(population);

    }

    getline(inFS, state);

    statePopulation.push_back(temp);

}

inFS.close();

cin >> zip;

for (i = 0; i < zipCodeState.size(); ++i) {

 }

for (i = 0; i < abbrevState.size(); ++i) {

 }

for (i = 0; i < statePopulation.size(); ++i) {

}

}

Statepair.h

#ifndef STATEPAIR

#define STATEPAIR

#include <iostream>

using namespace std;

template<typename T1, typename T2>

class StatePair {

private:

T1 key;

T2 value;

public:

StatePair()

{}

void SetKey(T1 key)

{

this->key = key;

}

void SetValue(T2 value)

{

this->value = value;

}

T1 GetKey() { return key;}

T2 GetValue() { return value;}

void PrintInfo()

{

cout<<key<<" : "<<value<<endl;

}

};

3 0
2 years ago
Learning in a digital environment is also called [blank] learning.
Dafna1 [17]

Answer:

The blank is online learning

4 0
3 years ago
Read 2 more answers
What command would you issue from a command prompt to see a listing of the computers in your workgroup?
ololo11 [35]
<span>Net View is the command issue from a command prompt to see a listing of the computers in your workgroup.It will display the list of domains,computers resources which have been shared by the specified computer then it will list all computers currently in our domain.The syntax for net view using command prompt NET VIEW [\\computername [/CACHE] | [/ALL] | /DOMAIN[:domainname]].</span>
8 0
3 years ago
If a menu item requires additional information from the user, the Windows standard is to place a(n) ____ at the end of the capti
elena-s [515]

Answer:

elipses

Explanation:

According to my research on information technology, I can say that based on the information provided within the question the windows standard in this situation would be to place an ellipses at the end of the caption. This is because in the English language an ellipses (...)  usually indicates an intentional omission of a word or sentence, which in computer science is used to give the user an indication that it requires further user input.

I hope this answered your question. If you have any more questions feel free to ask away at Brainly.

4 0
3 years ago
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