Answer:
b(b/a)^2
Step-by-step explanation:
Given that the value of the car depreciates such that its value at the end of each year is p % less than its value at the end of the previous year and that car was worth a dollars on December 31, 2010 and was worth b dollars on December 31, 2011, then
b = a - (p% × a) = a(1-p%)
b/a = 1 - p%
p% = 1 - b/a = (a-b)/a
Let the worth of the car on December 31, 2012 be c
then
c = b - (b × p%) = b(1-p%)
Let the worth of the car on December 31, 2013 be d
then
d = c - (c × p%)
d = c(1-p%)
d = b(1-p%)(1-p%)
d = b(1-p%)^2
d = b(1- (a-b)/a)^2
d = b((a-a+b)/a)^2
d = b(b/a)^2 = b^3/a^2
The car's worth on December 31, 2013 = b(b/a)^2 = b^3/a^2
Answer: The second one if im wrong please dont get maddd :(
but 80% im ure its right
Step-by-step explanation:
Both by Pythagorean theorem and dot product approaches, we find that the magnitude of the vector <u>u</u> = <4, 7> is equal to √65.
<h3>What is the magnitude of a vector?</h3>
Vectors are characterized by two elements: Magnitude and direction, the magnitude is a scalar that represents the <em>"length"</em> of the vector, while the direction indicate the <em>"orientation"</em> of the vector. There are two methods to find the magnitude of the vector u:
Method 1 - Pythagorean theorem
<u>u</u> = <4, 7>
u = √(4² + 7²)
u = √65
Method 2 - Dot product
<u>u</u> = <4, 7>
u = √(u • u)
u = √[(4, 7) • (4, 7)]
u = √(4² + 7²)
u = √65
Both by Pythagorean theorem and dot product approaches, we find that the magnitude of the vector <u>u</u> = <4, 7> is equal to √65.
To learn more on vectors: brainly.com/question/13322477
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Answer:
ok what do u want me to find sir.
Step-by-step explanation:
explain and i will answer.
Step-by-step explanation:
2 and 5 are coefficients
2x+3 is a sum
2x, 4, 3, and 5y are terms
(2x+3) ÷ 5y is a quotient
4(2x+3), 2x and 5y are products
2,4,5,x,y are factors
Hope I helped!