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Rzqust [24]
2 years ago
6

Hans rented a truck for one day. There was a base fee of $15.95, and there was an additional charge of 77 cents for each mile dr

iven. Hans had to pay
$207,68 when he returned the truck. For how many miles did he drive the truck?
Mathematics
2 answers:
Monica [59]2 years ago
7 0

Answer: 249 miles

Step-by-step explanation:

<em>First write a function that represents the amount paid for renting a truck:</em>

  • Set x as each mile driven.
  • Set y as the total amount paid.
  • $15.95 is the base fee paid no matter the mile, meaning the rent start at $15.95, not 0.

<em>Function: y = mx + b</em>

  • m = slope = amount paid for each mile driven = 77¢ = $0.77
  • b = y-intercept = amount paid when 0 miles driven = base fee = $15.95

<u>y = 0.77x + 15.95</u>

<em>He paid a total of $207.68, therefore y = 207.68:</em>

207.68 = 0.77x + 15.95

<em>Solve the equation for x:</em>

207.68 - 15.95 = 0.77x

191.73 = 0.77x

x = 249 miles driven

geniusboy [140]2 years ago
4 0
6.75 because I did this already
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in a choir the ratio of men to woman is 4:7. 25% of the men prefer classical songs, and 80% of the women prefer classical songs.
Paraphin [41]

Answer:

60%

Step-by-step explanation:

percentage of men in the choir = (4/11) x 100 = 36.4%

percentage of women in the choir = (7/11) x 100 = 63.6%

Percentage of men in the choir that prefer classical songs =  36.4 x0.25 = 9.1%

Percentage of women in the choir that prefer classical songs = 0.8 x 63.6% = 50.9%

percentage of the choir prefer classical songs = 50.9% + 9.1% = 60%

4 0
3 years ago
A confidence interval (CI) is desired for the true average stray-load loss u (watts) for a certain type of induction motor when
Genrish500 [490]

Answer:

A) CI = (57.12 , 59.48)

B) CI = (57.71 , 58.89)

C) CI = (57.53 , 59.07)

D) n = 239.63

Step-by-step explanation:

a)

given data:

mean, \bar X = 58.3

standard deviation, σ = 3

sample size, n = 25Given CI level is 95%, hence α = 1 - 0.95 = 0.05

α/2 = 0.05/2 = 0.025,

Zc = Z(α/2) = 1.96

ME = Zc * σ \sqrt{n}

ME = 1.96 * 3 \sqrt{25}

ME = 1.18

CI = (\bar X - Zc * s\sqrt{n}  , \barX + Zc * s\sqrt{n})

CI = (58.3 - 1.96 * 3\sqrt{25} , 58.3 + 1.96 * 3\sqrt{25})

CI = (57.12 , 59.48)

b)

Given data:

mean, \bar X = 58.3

standard deviation, σ = 3

sample size, n = 100

Given CI level is 95%, hence α = 1 - 0.95 = 0.05

α/2 = 0.05/2 = 0.025, Zc = Z(α/2) = 1.96

ME = zc * σ \sqrt{n}

ME = 1.96 * 3\sqrt{100}

ME = 0.59

CI = (\bar X - Zc * s\sqrt{n}  , \barX + Zc * s\sqrt{n})

CI = (58.3 - 1.96 * 3\sqrt{100} , 58.3 + 1.96 * 3\sqrt{100})

CI = (57.71 , 58.89)

c)

sample mean, \bar X = 58.3

sample standard deviation, σ = 3

sample size, n = 100

Given CI level is 99%, hence α = 1 - 0.99 = 0.01

α/2 = 0.01/2 = 0.005, Zc = Z(α/2) = 2.58

ME = Zc * σ \sqrt{n}

ME = 2.58 * 3\sqrt{100}

ME = 0.77

CI = (\bar X - Zc * s\sqrt{n}  , \barX + Zc * s\sqrt{n})

CI = (58.3 - 2.58 * 3\sqrt{100} , 58.3 + 2.58 * 3/\sqrt{100}

CI = (57.53 , 59.07)

D)

Given data:

Significance Level, α = 0.01,

Margin or Error, E = 0.5,

σ = 3

The critical value for α = 0.01 is 2.58.

for calculating population mean we used

n \geq (zc *σ/E)^2

n = (2.58 * 3/0.5)^2

n = 239.63

7 0
3 years ago
Help 15 points!!!!!!!!!!!!!!!!!!!!!
Svetllana [295]

Answer:

see explanation

Step-by-step explanation:

Using the tangent ratio in the right triangle

tan A = \frac{opposite}{adjacent} = \frac{BC}{AC} = \frac{7}{8} , then

∠ A = tan^{-1} (\frac{7}{8} ) ≈ 41° ( to the nearest degree )

The sum of the angles in the triangle = 180° , then

∠ B + 41° + 90° = 180°

∠ B + 131° = 180° ( subtract 131° from both sides )

∠ B = 49°

Using Pythagoras' identity in the right triangle

AB² = BC² + AC² = 7² + 8² = 49 + 64 = 113 ( take square root of both sides )

AB = \sqrt{113} ≈ 10.6 ( to the nearest tenth )

3 0
2 years ago
The relation described in this statement can be classified as which of the following? The total distance traveled and the time s
Rzqust [24]
<span>The relation described in this statement can be classified as </span><span>both a relation and a function. </span>
7 0
2 years ago
Which of the following is the inverse of y=12^x
Elenna [48]
y=12^x\ \ \ |log_{12}\\\\\log_{12}y=\log_{12}12^x\\\\\log_{12}y=x\log_{12}12\\\\x=\log_{12}y


y=12^x\to y^{-1}=\log_{12}x;\ x\in\mathbb{R^+}\to\ y^{-1}=\dfrac{\log x}{\log12};\ x\in\mathbb{R^+}\to y^{-1}=\dfrac{\ln x}{\ln 12}

Used:\\\\\log_aa=1\\\\\log_ab^n=n\log_ab\\\\\log_ab=\dfrac{\log_cb}{\log_ca}
3 0
3 years ago
Read 2 more answers
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