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rodikova [14]
3 years ago
8

Hi:) for triangle inequalities , the sum of two sides of a triangle has to be greater than the third side.

Mathematics
1 answer:
Jet001 [13]3 years ago
8 0

Answer:

NO

Step-by-step explanation:

Note :

Consider a triangle with sides‘s length a , b and c

triangle inequalities state that we must have c - a < b < c + a

now , is the third side always the longest ?

the answer is NO: (let’s take a counter example )

in a triangle with 2 sides‘s length 3 , 4

the third side could measure 2

because 4-3 < 2 < 4+3

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Sonja [21]
You would multiply by -4/3. That's cuz to get to 1, you have to cancel out the negative, with another negative. You then have to multiply by the reciprocal. 

Hope this helps! 
7 0
3 years ago
The following data gives the speeds (in mph), as measured by radar, of 10 cars traveling north on I-15. 76 72 80 68 76 74 71 78
____ [38]

Answer:

71.123 mph ≤ μ ≤ 77.277 mph

Step-by-step explanation:

Taking into account that the speed of all cars traveling on this highway have a normal distribution and we can only know the mean and the standard deviation of the sample, the confidence interval for the mean is calculated as:

m-t_{a/2,n-1}\frac{s}{\sqrt{n} } ≤ μ ≤ m+t_{a/2,n-1}\frac{s}{\sqrt{n} }

Where m is the mean of the sample, s is the standard deviation of the sample, n is the size of the sample, μ is the mean speed of all cars, and t_{a/2,n-1} is the number for t-student distribution where a/2 is the amount of area in one tail and n-1 are the degrees of freedom.

the mean and the standard deviation of the sample are equal to 74.2 and 5.3083 respectively, the size of the sample is 10, the distribution t- student has 9 degrees of freedom and the value of a is 10%.

So, if we replace m by 74.2, s by 5.3083, n by 10 and t_{0.05,9} by 1.8331, we get that the 90% confidence interval for the mean speed is:

74.2-(1.8331)\frac{5.3083}{\sqrt{10} } ≤ μ ≤ 74.2+(1.8331)\frac{5.3083}{\sqrt{10} }

74.2 - 3.077 ≤ μ ≤ 74.2 + 3.077

71.123 ≤ μ ≤ 77.277

8 0
2 years ago
the ratio of reds to greens was 5 to 16 and six times the number of reds exceeded the number of greens by 112. how many were red
Masja [62]
Call red as X then X/Green =5/16 => green = 16X/5.
six times the number of reds exceeded the number of green by 112 => 6X-16X/5=112 => 14X/5=112 => X= 40 => reds:40 => green = 128
7 0
3 years ago
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iren [92.7K]
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faust18 [17]

Answer:

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I had the wrong answer before sry haha

4 0
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