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3 years ago

5

Tom predicted that the Giants what score three point field goal scored two 6 points touchdowns in for one extra points if Tom we

re correct what would the Giants score be at the end of the game

1 answer:

frozen [14]3 years ago

4 0

If they only scored one field goal they would start with 3, and if they scored one extra point on each touchdown that would be 7+7+3 that would equal 17. If they only scored one extra point between two touchdowns than it would be 3+7+6=16

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Part A: Determine if the expression is one of our special products. If so, identify it by its general form:

kondaur [170]

Answer:

1.

Part A: Yes, it is (a - b)².

Part B: a² - 2ab + b² => (x - 6)² = x² - 12x + 36.

Part C: x² - 12x + 36.

2.

Part A: Not a special product.

Part B: Binomial distribution => (x + 8)(x + 1) = x² + 9x + 8.

Part C: x² + 9x + 8.

3.

Part A: Yes, it is (a + b)²

Part B: a² + 2ab + b² => (3x + 2)² = 9x² + 12x + 4.

Part C: 9x² + 12x + 4.

4.

Part A: Yes, it is (a + b)(a - b), a difference of squares.

Part B: a² - b² => 4x² - 49

Part C: 4x² - 49

5.

Part A: Not a special product.

Part B: Binomial distribution => (x - 5)(2x - 5) = 2x² - 15x + 25.

Part C: 2x² - 15x + 25

6 0

3 years ago

What is 26,752 rounded to the nearest ten thousand

Licemer1 [7]

Answer:

27,000 I think it's rii

5 0

3 years ago

Lots of points:

Makovka662 [10]

480 + 192 = 672 students total
16 + 12 = 28 classrooms total
672/28 = 24 students per room
24 * 12 = 288 students that need to be in school B
288 - 192 = 96 students who have to transfer

5 0

3 years ago

Read 2 more answers

We take a milk carton from the refrigerator and put it on the table at room temperature. We assume that the temperature of the c

Kisachek [45]

We can solve this problem using separation of variables.

Then apply the initial conditions

EXPLANATION

We were given the first order differential equation

$\frac{dT}{dt}=k(T-a)$

We now separate the time and the temperature variables as follows,

$\frac{dT}{T-a}=kdt$

Integrating both sides of the differential equation, we obtain;

$ln(T-a)=kt +c$

This natural logarithmic equation can be rewritten as;

$T-a=e^{kt +c}$

Applying the laws of exponents, we obtain,

$T-a=e^{kt}\times e^{c}$

$T-a=e^{c}e^{kt}$

We were given the initial conditions,

$T(0)=4$

Let us apply this condition to obtain;

$4-20=e^{c}e^{k(0)}$

$-16=e^{c}$

Now our equation, becomes

$T-a=-16e^{kt}$

or

$T=a-16e^{kt}$

When we substitute a=20,
we obtain,

$T=20-16e^{kt}$

b) We were also given that,

$T(5)=8$

Let us apply this condition again to find k.

$8=20-16e^{5k}$

This implied

$-12=-16e^{5k}$

$\frac{-12}{-16}=e^{5k}$

$\frac{3}{4}=e^{5k}$

We take logarithm to base e of both sides,

$ln(\frac{3}{4})=5k$

This implies that,

$\frac{ln(\frac{3}{4})}{5}=k$

$k=-0.2877$

After 15 minutes, the temperature will be,

$T=20-16e^{-0.2877\times 15}$

$T=20-0.21376$

$T=19.786$

After 15 minutes, the temperature is approximately 20°C

6 0

3 years ago

A water sprinkler sends out water in a circular pattern. How many feet away from the sprinkler can it spread water is the area f

PSYCHO15rus [73]

Answer:

r= 13ft

Step-by-step explanation:

You are looking for the radius

The Area of a circle is

πr2=530.66

(3.14)r2=530.66

Divide both sides by 3.14

r2=169

Square root both sides to get radius

r=13 feet

6 0

3 years ago