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3 years ago

Can somebody please help me with this question I need help ASAP

Mathematics

2 answers:

S_A_V [24]3 years ago

4 0

I think that the doctor would see 72 patients in 1 year.

Alenkasestr [34]3 years ago

3 0

The doctor would have 72 patients each week. Meaning 3744 each year.

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Properties of exponents<br> Rewrite the expression in the form b^n—— (b^2)^3/7

exis [7]

Answer:

$b^{\frac{6}{7}}$ is the required expression.

Step-by-step explanation:

$(b^2)^{\frac{3}{7}}\\\\\mathrm{Apply\:exponent\:rule:\:}\left(a^b\right)^c=a^{bc},\:\quad \mathrm{\:assuming\:}a\ge 0\\\\=b^{2\cdot \frac{3}{7}}\\\\=b^{\frac{6}{7}}$

Best Regards!

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3 years ago

n many population growth problems, there is an upper limit beyond which the population cannot grow. Many scientists agree that t

givi [52]

Answer:

$\frac{dP}{dt} = rP(1 - \frac{P}{K}) = 0.017P(1 - \frac{P}{16})$

Step-by-step explanation:

The logistic function of population growth, that is, the solution of the differential equation is as follows:

$P(t) = \frac{KP_{0}e^{rt}}{K + P_{0}(e^{rt} - 1)}$

We use this equation to find the value of r.

In this problem, we have that:

$K = 16, P_{0} = 2, P(50) = 4$

So we find the value of r.

$P(t) = \frac{KP_{0}e^{rt}}{K + P_{0}(e^{rt} - 1)}$

$4 = \frac{16*2e^{50r}}{16 + 2*(e^{50r} - 1)}$

$4 = \frac{32e^{50r}}{14 + 2e^{50r}}$

$56 + 8e^{50r} = 32e^{50r}}$

$24e^{50r} = 56$

$e^{50r} = 2.33$

Applying ln to both sides of the equality

$50r = 0.8459$

$r = 0.017$

The differential equation is

$\frac{dP}{dt} = rP(1 - \frac{P}{K}) = 0.017P(1 - \frac{P}{16})$

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3 years ago

Evaluate the expression 4(3h - 6) for h = 4.

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Answer: 24

Step-by-step explanation:

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Is this a direct variation? for #1

FinnZ [79.3K]

No its not because it dont go up by a constant rate of change

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3 years ago

Which of the following is NOT a way to describe slope? *

mina [271]

Answer:

rise over

Step-by-step explanation:

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3 years ago

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