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Lesechka [4]
3 years ago
7

I am studying for a Calculus test and have the answers for the study guide but I'm having trouble with problems 2, 3, 4 (finding

maximums and minimums for each) as well as #9 (computing the limit). The answers are written next to each question.

Mathematics
1 answer:
Mariulka [41]3 years ago
4 0
#2) Use quotient rule
\frac{f'g - fg'}{g^2}
Remember for solving log equations:
e^{ln x} = x

#3) Derivative of tan = sec^2 = 1/cos^2
Domain of tan is [-pi/2, pi/2], only consider x values in that domain.

#4 Use Quotient rule

#9  Use double angle identity for tan
tan(2x) = \frac{2tan x}{1-tan^2 x}
This way you can rewrite tan(pi/2) in terms of tan(pi/4).
Next use L'hopitals rule, which says the limit of indeterminate form(0/0) equals limit of quotient of derivatives of top/bottom of fraction.

Take derivative of both top part and bottom part separately, then reevaluate the limit. <span />
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I'm almost done with schooling any help?​
melisa1 [442]

Answer:

The ordered pair that corresponds to point P is: (4, 2)

Step-by-step explanation:

It is clear from the graph that the point P is located at the location (4, 2).

In other words,

at x = 4, y = 2

It means:

The x-coordinate of the point P is: x = 4

The y-coordinate of the point P is: y = 2

Thus, the location of the point P →  P(x, y) = P(4, 2)

Please check the attached graph.

Therefore, we conclude that:

The ordered pair that corresponds to point P is: (4, 2)

6 0
3 years ago
Look at the pictures and solve. WILL GIVE BRAINIEST
Reika [66]

Answer:

1. y = 4x - 4

2. y = x + 2

3. y = -2x - 4

4. y = -x + 2

Step-by-step explanation:

Slope-intercept form is y = mx+b. As we know, m is the slope and b is the y-intercept. We need to find the slope and y-intercept and put them in the equation. Slope is rise over run, so we just count up then over until we get to an intersection. For the y-intercept, we look where the line crosses the y-axis.

3 0
3 years ago
How many extraneous solutions exist for the logarithmic equation below if it is solved in the most efficient way possible?log_(2
Nadusha1986 [10]

Answer:

No extraneous solution

Step-by-step explanation:

We have the logarithmic equation given by,

\log_{2}[\log_{2}(\sqrt{4x})]=1

i.e. \log_{2}(\sqrt{4x})=2^{1}

i.e. \sqrt{4x}=2^{2}

i.e. \sqrt{4x}=4

i.e. 4x=4^{2}

i.e. 4x=16

i.e. x=4

So, the solution of the given equation is x=4.

Now, as we domain of square root function is x > 0 and also, the domain of logarithmic function is ( 0,\infty ).

Therefore, the domain of the given function is x > 0.

We know that the extraneous solution is the solution which does  not belong to the domain.

But as x=4 belongs to the domain x > 0.

Thus, x = 4 is not an extraneous solution.

Hence, this equation does not have any extraneous solution.

7 0
3 years ago
Read 2 more answers
What’s the slope of the line on the graph?
Anuta_ua [19.1K]
The slope would be 2x
7 0
3 years ago
Write various of the equation of a line that passes through (-6, 3) and has a slope of - 1/3
pishuonlain [190]

Answer:

\large\boxed{y-3=-\dfrac{1}{3}(x+6)-\text{point-slope form}}\\\boxed{y=-\dfrac{1}{3}x+1-\text{slope-intercept form}}\\\boxed{x+3y=3-\text{standard form}}

Step-by-step explanation:

The point-slope form of an equation of a line:

y-y_1=m(x-x_1)

m - slope

We have

m=-\dfrac{1}{3},\ (-6,\ 3)\to x_1=-6,\ y_1=3

Substitute:

y-3=-\dfrac{1}{3}(x-(-6))\\\\y-3=-\dfrac{1}{3}(x+6)

Convert to the slope-intercept form

y=mx+b

y-3=-\dfrac{1}{3}(x+6)           <em>use the distributive property</em>

y-3=-\dfrac{1}{3}x-2           <em>add 3 to both sides</em>

y=-\dfrac{1}{3}x+1

Convert to the standard form

Ax+By=C

y=-\dfrac{1}{3}x+1           <em>multiply both sides by 3</em>

3y=-x+3             <em>add x to both sides</em>

x+3y=3

5 0
3 years ago
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