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2 years ago

PLEASE HELP ASAP! TYSMM

Mathematics

1 answer:

DerKrebs [107]2 years ago

7 0

This is in the lower right corner and is a right triangle. So we use the Area calculation of a right triangle.

<u>ab</u> = <u>(4)(2)</u> The height is given as 4 in and we know the base is 2 in
2 2 We know this because the top right distance is given as 2

8 / 2 = 4 square inches

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Let b be a number such that (2b+5)(b-1)=6b. What is the largest possible value of b? Express your answer as a common fraction.

Oksi-84 [34.3K]

Answer:

Foil the expression and solve the derivative with respect to b at f'(x)=0 $2b^2+3b+5=6b\\d/dx(2b^2+9b+5=0)\\4b+9=0\\b=-9/4$

Step-by-step explanation:

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2 years ago

You saved $250.00 to spend over the summer. You decide

Ludmilka [50]

Answer:

1 minor thing. you made a mistake it is $25.00 not $25,00. But the answer is this.

Step-by-step explanation:

250.00÷25.00= 10.

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2 years ago

Read 2 more answers

Find the volume of the wedge with vertices at points (0,0,0), (1,0,0), (0,1,0), (0,0,1) by integrating the area of cross-section

Angelina_Jolie [31]

Answer:

V = 1/6 cubic units

Step-by-step explanation:

Applying the concept of integrals for volume calculation:

$V = \int\limits^b_a {S(x)} \, dx$ (1)

V = volume of the solid bounded by x = a and x = b

S(x) = cross section area of the solid, perpendicular to the x axis

From the figure we have that S is the area of a triangle that has base Z and height Y

Area of the triangle = $S(x)=\frac{y(x)*z(x)}{2}$ (2)

Calculation of y(x) and z(x)

We apply the equation of the point-slope line (plane xy):

Slope = $m = \frac{y_{2} - y_{1} }{x_{2} - x_{1}}$ (3)

Equation of the line = $y - y_{1} =m(x-x_{1} )$ (4)

Replacing the points (1,0) and (0,1) in (3):

$m=\frac{1-0}{0-1} =-1$

Replacing the point (1,0) and m = -1 in (4):

$y-0=(-1)(x-1)$

y(x) = -x + 1 (Line A-B) (5)

We apply the equation of the point-slope line (plane xz):

Slope = $m = \frac{z_{2} - z_{1} }{x_{2} - x_{1}}$ (6)

Equation of the line = $z - z_{1} =m(x-x_{1} )$ (7)

Replacing the points (1,0) and (0,1) in (6):

$m=\frac{1-0}{0-1} =-1$

Replacing the point (1,0) and m = -1 in (7):

$z-0=(-1)(x-1)$

z(x) = -x + 1 (Line A-C) (8)

Replacing (5) and (8) in (2)

$S(x) = \frac{(-x + 1) * (-x + 1)}{2} =\frac{(-x + 1)^{2} }{2}$ (9)

Replacing (9) in (1) and knowing that a = 0 and b = 1:

$V = \int\limits^1_0 {\frac{(-x + 1)^{2} }{2}} \, dx = \int\limits^1_0 {\frac{x^{2}-2x+1 }{2}} \, dx$

$V =\frac{1}{2} (\frac{x^{3} }{3} -2\frac{x^{2} }{2} +x)$ evaluated from x=0 to x=1

$V= \frac{1}{2} (\frac{1}{3} -1 +1) = \frac{1}{6}$

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3 years ago

Could 18 in, 6 in, 13 in form a triangle

Tanya [424]

Answer: Yes

Step-by-step explanation:

The reason on why it could form a triangle because 18 is the highest side in the triangle and if you have 2 of the smaller sides that are greater than the larger size then you could form a triangle and 13 and 6 equals to 19 so you could make a triangle hopes this helps and have a good day.

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2 years ago

Y=0.575x+42 y-intercept

Juliette [100K]

Answer:

I'm sorry I cant solve this without an X value but if you tell me the x value i'd be glad to help you out in the comment section below.

Step-by-step explanation:

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3 years ago