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Virty [35]
4 years ago
10

You are graphing rectangle A, B, C, and D in the coordinate plane. The following are three of the vertices of the rectangle: A(-

7, -7.5), B(-3,-7.5), and C(-3, 2.5). What are the coordinates of point D? (image above)

Mathematics
1 answer:
topjm [15]4 years ago
8 0

Answer:

idk am in 6 grade lol i wish i could halp you

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A stamp has the Length of 1/2 cm and a width of 1 1/2 is the area of the stamps
avanturin [10]

Answer:

Area =  \frac{3}{4} cm^2

Step-by-step explanation:

Given

Length =\frac{1}{2}\ cm

Width = 1\frac{1}{2}\ cm

Required

Determine the Area

Area is calculated as follows

Area = Length * Width

Substitute values for Length and Width

Area = \frac{1}{2} * 1\frac{1}{2}

Convert mixed fraction

Area = \frac{1}{2} * \frac{3}{2}

Area =  \frac{3}{4}

Hence, the area is

Area =  \frac{3}{4} cm^2

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3 years ago
MY<br> LAST <br> QUESTION (NEED HELP ASAP) PLEASE!!!!
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Answer:

The answer is A

Step-by-step explanation:

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3 years ago
Awad claims that when m is a negative integer and n is a positive integer, n-m is
Lelu [443]

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3 years ago
Differentiate y=x⁴(1-2x⁵)⁶(5-8x³)².​
Liula [17]

Step-by-step explanation:

Let y(x)=f(x)g(x)h(x) where

f(x) = x^4

g(x)= (1 -2x^5)^6

h(x)= (5 - 8x^3)^2

so that

y(x) = x^4(1 -2x^5)^6(5 - 8x^3)^2

Recall that the derivative of the product of functions is

y'(x)=f'(x)g(x)h(x)+f(x)g'(x)h(x)+f(x)g(x)h'(x)

so taking the derivatives of the individual functions, we get

f'(x) = 4x^3

g'(x) = 6(1 - 2x^5)^5(-10x^4)

h'(x) = 2(5 - 8x^3)(-24x^2)

So the derivative of y(x) is given by

y'(x) = 4x^3(1 -2x^5)^6(5 - 8x^3)^2 +  x^4 6(1 -2x^5)^5(-10x^4)(5 - 8x^3)^2 +  x^4(1 -2x^5)^6 2(5 - 8x^3)(-24x^2)

or

y'(x) = 4x^3(1 -2x^5)^6(5 - 8x^3)^2

\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:- 60x^8(1 -2x^5)^5(5 - 8x^3)^2

\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:- 48x^6(1 -2x^5)^6 2(5 - 8x^3)

3 0
3 years ago
What are the coordinates of point A?​
Ratling [72]

Answer:

  (d)  (7, -5)

Step-by-step explanation:

The x-coordinate is listed first in an ordered pair. It is found on the horizontal scale. The point is on the grid line halfway between 6 and 8, so is presumed to have an x-coordinate of 7.

The y-coordinate is listed second in an ordered pair. It is found on the vertical scale. The point is on the grid line halfway between -4 and -6, so is presumed to have a y-coordinate of -5.

The coordinates of point A are (x, y) = (7, -5).

__

<em>Additional comment</em>

As in the case here, you will often run across graphs that don't have markings on every grid line You are expected to be able to figure out the value of a grid line based on the spacing of the marked lines.

It is a good idea to get familiar with reading coordinates of a point on a graph, as you will be doing it a lot.

4 0
2 years ago
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