Answer:
(1,1) (2,2) (1,2) (1,5) (4,4) (4,5)
there are a lot more but those are some.
Step-by-step explanation:
Check the picture below, notice those three quadrilaterals, bearing in mind that a square and rhombus both have equal sides all around.
1. Given any triangle ABC with sides BC=a, AC=b and AB=c, the following are true :
i) the larger the angle, the larger the side in front of it, and the other way around as well. (Sine Law) Let a=20 in, then the largest angle is angle A.
ii) Given the measures of the sides of a triangle. Then the cosines of any of the angles can be found by the following formula:
a^{2}=b ^{2}+c ^{2}-2bc(cosA)
2.
20^{2}=9 ^{2}+13 ^{2}-2*9*13(cosA) 400=81+169-234(cosA) 150=-234(cosA) cosA=150/-234= -0.641
3. m(A) = Arccos(-0.641)≈130°,
4. Remark: We calculate Arccos with a scientific calculator or computer software unless it is one of the well known values, ex Arccos(0.5)=60°, Arccos(-0.5)=120° etc
If you would like to simplify <span>7 - 3[(n^3 + 8n) / (-n) + 9n^2], you can do this using the following steps:
</span>7 - 3[(n^3 + 8n) / (-n) + 9n^2] = 7 - 3[(-n^2 - 8) + 9n^2] = 7 - 3[-n^2 - 8 + 9n^2] = 7 - 3[ - 8 + 8n^2] = 7 - 3[8<span>n^2 - 8] = 7 - 24n^2 + 24 = - 24n^2 + 31
</span>
The correct result would be <span>- 24n^2 + 31.</span>
Answer:
1+1+2
Step-by-step explanation:
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