3 years ago

Please Help!

Mathematics

1 answer:

liraira [26]3 years ago

3 0

The turning point is at (2, 3)
F(-7) = -1.

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Answer:

144

Step-by-step explanation:

2( 1/2 × 3 × 4 ) + ( 11 × 5) + ( 11 × 4 ) + ( 11 × 3)

= 12 + 55 + 44 + 33

= 144

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PLEASE HELP WILL GIVE BRAINLIEST! What is the following sum? Assume x > or equal to 0 and y is > or equal to 0.

Ira Lisetskai [31]

Answer:

Option (b) is correct.

The sum of given expression $\sqrt{x^2y^3}+2\sqrt{x^3y^4}+xy\sqrt{y}$ is $2xy\sqrt{y}+2xy^2\sqrt{x}$

Step-by-step explanation:

Given:Expression $\sqrt{x^2y^3}+2\sqrt{x^3y^4}+xy\sqrt{y}$

We have to find the sum of the given expression and choose the correct from the given options.

Consider the given expression $\sqrt{x^2y^3}+2\sqrt{x^3y^4}+xy\sqrt{y}$ .

$\sqrt{x^2y^3}$ can be written as $\sqrt{x^2y^2y}=xy\sqrt{y}$

Also, $2\sqrt{x^3y^4}$ can be written as $2\sqrt{x^3y^4}=2\sqrt{x^2x(y^2)^2}=2xy^2\sqrt{x}$

Now, the given expression becomes,

$\sqrt{x^2y^3}+2\sqrt{x^3y^4}+xy\sqrt{y}$

$=xy\sqrt{y}+2xy^2\sqrt{x}+xy\sqrt{y}$ .

Now, adding like term, terms having same variable with same degree.

$=2xy\sqrt{y}+2xy^2\sqrt{x}$ .

Thus, The sum of given expression $\sqrt{x^2y^3}+2\sqrt{x^3y^4}+xy\sqrt{y}$ is $2xy\sqrt{y}+2xy^2\sqrt{x}$

3 0

3 years ago