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4 years ago

A paper company produces 1,740 notebooks in 2 days. How many notebooks can it produce in 10 days?

Mathematics

1 answer:

vladimir1956 [14]4 years ago

8 0

Answer: in 10 days the company can make 87000 notebooks considering the company produces at the same rate.

Step-by-step explanation:

Think 1740=2d

X=10d

Cross multiply

2x= 17400

X= 8700

8700 x 10d = 87000

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What is the value of x?? please help

DaniilM [7]

Answer:

x=64

Step-by-step explanation:

Both the semicircle that says 180, and the right angle sign in the image serve to support the idea that all parts of the figure equal 90

Therefore, it is safe to say that you need to subtract 26 from 90 in order to solve for x.

90-26 = 64

8 0

3 years ago

Read 2 more answers

Can someone please help me please I really need help please help

mr Goodwill [35]

Answer:

K'(4, -4)
L'(8, -4)
M'(8, 8)
N'(4, 8)

Step-by-step explanation:

Dilation centered at the origin multiplies every coordinate value by the scale factor.

K(1, -1) ⇒ K' = 4(1, -1) = (4, -4)

L(2, -1) ⇒ L' = 4(2, -1) = (8, -4)

M(2, 2) ⇒ M' = 4(2, 2) = (8, 8)

N(1, 2) ⇒ N' = 4(1, 2) = (4, 8)

6 0

3 years ago

A student received an 82% on an exam. If there were 50 questions on the exam, which ratio would show the number of questions ans

cluponka [151]

Easy

82% correct
82 out of 100 correct
82/100 of ttoal correct
total=50
82/100 times 50=
41/50 times 50=41 correct

ratio is 41:50

B is answer

5 0

3 years ago

Read 2 more answers

What is the range of arcsinx

Aleonysh [2.5K]

Y= arcsin(x) is equivalent to sin(y) = x

we know that -1≤x+1, hence the range of y is: -π/2≤y≤+π/2

3 0

3 years ago

out of some students appeared in an examination 80% passed in mathematics 75% passed in english and 5% failed in both subjects i

Advocard [28]

Answer:

5000 students appeared in the examination.

Step-by-step explanation:

We solve this question using Venn probabilities.

I am going to say that:

Event A: Passed in Mathematics

Event B: Passed in English.

5% failed in both subjects

This means that 100 - 5 = 95% pass in at least one, which means that $P(A \cup B) = 0.95$

80% passed in mathematics 75% passed in english

This means that $P(A) = 0.8, P(B) = 0.75$

Proportion who passed in both:

$P(A \cap B) = P(A) + P(B) - P(A \cup B)$

Considering the values we have for this problem

$P(A \cap B) = P(A) + P(B) - P(A \cup B) = 0.8 + 0.75 - 0.95 = 0.6$

3000 of them were passed both subjects how many students appeared in the examination?

3000 is 60% of the total t. So

$0.6t = 3000$

$t = \frac{3000}{0.6}$

$t = 5000$

5000 students appeared in the examination.

4 0

3 years ago