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3 years ago

A paper company produces 1,740 notebooks in 2 days. How many notebooks can it produce in 10 days?

Mathematics

1 answer:

vladimir1956 [14]3 years ago

8 0

Answer: in 10 days the company can make 87000 notebooks considering the company produces at the same rate.

Step-by-step explanation:

Think 1740=2d

X=10d

Cross multiply

2x= 17400

X= 8700

8700 x 10d = 87000

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The two squares x and y are mathematically similar. The areas of x and y are 17cm squared and 272cm squared, respectively. The l

Rasek [7]

I would set this up as a a proportion:
$\frac{17cm}{5cm}$ · $\frac{272cm}{x}$
17x = 1360
x = 20 cm

6 0

3 years ago

Albie's total income is $695.25 in a week

ikadub [295]

Answer:

Step-by-step explanation:

7.5/100= .075

$580000 x .075 = $43,500 commission

5 0

3 years ago

Factorise the following:<br><img src="https://tex.z-dn.net/?f=%7B3x%7D%5E%7B2%7D%20%20%2B%205x%20-%2012" id="TexFormula1" title=

Fed [463]

Answer:

(x + 3)(3x - 4)

Step-by-step explanation:

Given

3x² + 5x - 12

Consider the factors of the product of the coefficient of the x² term and the constant term which sum to give the coefficient of the x- term.

product = 3 × - 12 = - 36 and sum = + 5

The factors are + 9 and - 4

Use these factors to split the x- term

3x² + 9x - 4x - 12 ( factor first/second and third/fourth terms )

= 3x(x + 3) - 4(x + 3) ← factor out (x + 3) from each term

= (x + 3)(3x - 4)

Thus

3x² + 5x - 12 = (x + 3)(3x - 4) ← in factored form

6 0

3 years ago

At a certain university, the average attendance at basketball games has been 3125. Due to the dismal showing of the team this ye

Neporo4naja [7]

Answer:

The test statistic needed to evaluate the claim is t = -1.08.

Step-by-step explanation:

The test statistic is:

$t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}$

In which X is the sample mean, $\mu$ is the expected value of the mean, s is the standard deviation of the sample and n is the size of the sample.

At a certain university, the average attendance at basketball games has been 3125. The athletic director claims that the attendance is the same as last year.

This means that $\mu = 3125$

Due to the dismal showing of the team this year, the attendance for the first 9 games has averaged only 2915 with a standard deviation of 585.

This means that $n = 9, X = 2915, s = 585$

What is the test statistic needed to evaluate the claim?

$t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}$

$t = \frac{2915 - 3125}{\frac{585}{\sqrt{9}}}$

$t = -1.08$

The test statistic needed to evaluate the claim is t = -1.08.

6 0

2 years ago

Whats 24 over 74 in fraction form?

kompoz [17]

24/74 simplified is 12/37

3 0

3 years ago

Read 2 more answers