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GrogVix [38]
3 years ago
7

Evaluate the definite integral. 1/4 csc(2πt) cot(2πt) dt 1/12

Mathematics
1 answer:
Afina-wow [57]3 years ago
5 0
Hey there, hope I can help!

\frac{1}{4}\csc \left(2\pi t\right)\cot \left(2\pi t\right)dt\frac{1}{12}

\mathrm{Multiply\:fractions}: \:a\cdot \frac{b}{c}\cdot \frac{d}{e}=\frac{a\:\cdot \:b\:\cdot \:d}{c\:\cdot \:e} \ \textgreater \  \frac{1\cdot \:1\cdot \:dt}{4\cdot \:12}\csc \left(2\pi t\right)\cot \left(2\pi t\right)

\mathrm{Apply\:rule}\:1\cdot \:a=a \ \textgreater \  \frac{dt}{4\cdot \:12}\csc \left(2\pi t\right)\cot \left(2\pi t\right)

\mathrm{Multiply\:the\:numbers:}\:4\cdot \:12=48 \ \textgreater \  \frac{dt}{48}\csc \left(2\pi t\right)\cot \left(2\pi t\right)

\mathrm{Multiply\:fractions}: \:a\cdot \frac{b}{c}=\frac{a\:\cdot \:b}{c} \ \textgreater \  \frac{dt\csc \left(2\pi t\right)\cot \left(2\pi t\right)}{48}

Hope this helps!
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Flying against the wind, an airplane travels 4340 kilometers in 7 hours. Flying with the wind, the same plane travels 3120 kilom
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The rate of the wind is given to be 210 the rate of the plane in mid air is given as 830

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In 7 hours the kilometer traveled =  4340

P + W = 4340/7

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3 years ago
At time t=0 hours, a tank contains 3000 litres of water. Water leaks from the tank. At the end of every hour there is x% less wa
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Answer:

x = 2; K = 0.98

Step-by-step explanation:

At time, t = 0, Volume of Water = 3,000 litres

After t hours , the Volume of water in the tank = Vt

At the end of every hour there is a x% less water in the tank then at the start of the hour

After 1 hour, volume of water left Vt = V1

V1 = 3,000 - 3000 × (x/100)

V1 = 3,000 - 30x

After 2 hours, Volume of water left is V2

V2 = (3,000 - 30 x) - (3,000 - 30 x) × (x/100)

V2 = (3,000 - 30 x) - (3000x - 30x²)/100

V2 = {100(3000 - 30x) - x(3000 - 30x)} /100

V2 = {(3000 - 30x)(100 - x)}/100

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(3000 - 30x)(100 - x) = 288120

300000 - 3000 x - 3000 x + 30 x² = 288120

30 x ² - 6000 x + 11880 = 0

Dividing both sides by 30

x² - 200 x + 396=0

Factorizing:

(x -198)(x-2) = 0

x = 198 or x = 2

Since the percentage by which the water reduces cannot be greater than 100, x = 2 is chosen.

Step 2: Solving for k

Given that Vt=KtV0

K = Vt/V0

At t = 1

V1 = 3000 - 30x

V1 = 3000 - 30 × 2

V1 = 3000 - 60

V1 = 2940

K = 2940/3000

K = 0.98

5 0
3 years ago
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