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3 years ago

A factory adds three red drops

Mathematics

1 answer:

frosja888 [35]3 years ago

5 0

Answer:

um does it have multiple choice by chance

Step-by-step explanation:

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Your parents gave you a gift card for your favorite coffee shop. The card was worth $50 when you got it. Each day, you buy a dri

nekit [7.7K]

Answer:

B. $y=-3x+50$

Step-by-step explanation:

Let x be number of days and y be value of card.

It has been given that your parents gave you a gift card for your favorite coffee shop. The card was worth $50 when you got it. Each day, you buy a drink for $3.

We can see that value of card is dependent on number of days as value of card decrease by 3 each day. This means that slope of our line will be -3.

As initially you have $50, this means that y-intercept of our given line will be 50.

Since we know that equation of a line in slope-intercept form is: $y=mx+b$ , where,

m = Slope of line.

b = y-intercept.

Upon substituting our given values in slope intercept form of equation we will get,

$y=-3x+50$

Therefore, the equation $y=-3x+50$ shows the value on the gift card over time.

8 0

3 years ago

Read 2 more answers

Please help asap pleaseeeeeeeeee ASAPPPPPPPPPP

zheka24 [161]

DUDE THESE WERE SO EASY I DID THIS IN 4TH GRADE YOYR TOO YOUNG OK OK

Answer: do L x W x H = a

7 0

3 years ago

Which equation in slope-intercept form represents a line that is parallel to y=−4x−5 and passes through the point (0,0)?

Contact [7]

Answer:

Step-by-step explanation:

The line is negative and it was shifted down 5 units meaning it goes through -5,0. It needs to move up five so y=-4x-5+5= y=-4x

6 0

4 years ago

Read 2 more answers

Of 3,000 pet owners surveyed 9% purchased their pets from a pet store how many pets were purchased from a pet store

Dima020 [189]

$9\%\cdot 3,000 = \frac{9}{100}\cdot 3,000 = 9\cdot 30 = 270$

8 0

3 years ago

P(k)=a^k=2 3 4 find value of a that makes this is a valid probability distribution

Vesna [10]

Sounds like you're asked to find $a$ such that

$\displaystyle\sum_{k=2}^4\mathbb P(k)=\mathbb P(2)+\mathbb P(3)+\mathbb P(4)=1$

In other words, find $a$ that satisfies

$a^2+a^3+a^4=1$

We can factorize this as

$a^4+a^3+a^2-1=a^3(a+1)+(a-1)(a+1)=(a+1)(a^3+a-1)=0$

In order that $\mathbb P(k)$ describes a probability distribution, require that $\mathbb P(k)\ge0$ for all $k$ , which means we can ignore the possibility of $a=-1$ .

Let $a=y+\dfrac xy$ .

$a^3+a-1=\left(y+\dfrac xy\right)^3+\left(y+\dfrac xy\right)-1=0$
$\left(y^3+3xy+\dfrac{3x^2}y+\dfrac{x^3}{y^3}\right)+\left(y+\dfrac xy\right)-1=0$

Multiply both sides by $y^3$ .

$y^6+3xy^4+3x^2y^2+x^3+y^4+xy^2-y^3=0$

We want to find $x\neq0$ that removes the quartic and quadratic terms from the equation, i.e.

$\begin{cases}3x+1=0\\3x^2+x=0\end{cases}\implies x=-\dfrac13$

so the cubic above transforms to

$y^6-y^3-\dfrac1{27}=0$

Substitute $y^3=z$ and we get

$z^2-z-\dfrac1{27}=0\implies z=\dfrac{9+\sqrt{93}}{18}$
$\implies y=\sqrt[3]{\dfrac{9+\sqrt{93}}{18}}$
$\implies a=\sqrt[3]{\dfrac{9+\sqrt{93}}{18}}-\dfrac13\sqrt[3]{\dfrac{18}{9+\sqrt{93}}}$

6 0

4 years ago