A factory adds three red drops

A health statistics agency in a certain country tracks the number of adults who have health insurance. Suppose according to the

Fynjy0 [20]

Answer:

a) 15.4% probability that a randomly selected person in this country is 65 or older

b) 0.023 = 2.3% probability that the person is 65 or older

Step-by-step explanation:

To solve b), i will use the Bayes Theorem.

Bayes Theorem:

Two events, A and B.

$P(B|A) = \frac{P(B)*P(A|B)}{P(A)}$

In which P(B|A) is the probability of B happening when A has happened and P(A|B) is the probability of A happening when B has happened.

(a) What is the probability that a randomly selected person in this country is 65 or older?

22.7% of people in the county are under age 18

61.9% are ages 18–64

p% are 65 or older.

The sum of those is 100%. So

22.7 + 61.9 + p = 100

p = 100 - (22.7+61.9)

p = 15.4

15.4% probability that a randomly selected person in this country is 65 or older.

(b) Given that a person in this country is uninsured, what is the probability that the person is 65 or older?

Event A: Uninsured

Event B: 65 or older.

15.4% probability that a randomly selected person in this country is 65 or older.

This means that $P(B) = 0.154$

1.4% of those 65 and older do not have health insurance.

This means that $P(A|B) = 0.014$

Probability of not having insurance.

22.7% are under 18. Of those, 5.4% do not have insurance.

61.9% are aged 18-64. Of those, 12.8% do not have insurance.

15.4% are 65 or over. Of those, 1.4% do not have health insurance. So

$P(A) = 0.227*0.054 + 0.619*0.128 + 0.154*0.014 = 0.093646$

Then

$P(B|A) = \frac{0.154*0.014}{0.093646} = 0.023$

0.023 = 2.3% probability that the person is 65 or older

5 0

3 years ago

STAR Co. provides paper to smaller companies whose volumes are not large enough to warrant dealing directly with the paper mill.

mamaluj [8]

Answer:

see below

Step-by-step explanation:

In order for the problem to make sense, we have to assume typos in Patterns 2, 3, and 4. We suppose they should be (0, 0, 3, 10), (8, 0, 0, 4) and (2, 1, 2, 1).

If we let p, q, r, s, t represent the number of rolls cut to patterns 1 to 5, respectively, then we want ...

minimize 10p +10q +4r +s +t . . . . . . . total trim loss

subject to ...

0p +0q +8r +2s +7t = 5672 . . . . . . number of 12-ft rolls

6p +0q +0r +1s +1t = 1670 . . . . . . . . number of 15-ft rolls

0p +3q +0r +2s +0t = 3200 . . . . . . number of 30-ft rolls

p≥0, q≥0, r≥0, s≥0, t≥0

_____

The solution works out to be (p, q, r, s, t) = (1, 0, 253, 1600, 64) with a trim loss of 2686 feet (equivalent to 27 100-ft rolls).

Note that we have endeavored to fill the order exactly. We don't know if there are cut choices that would minimize loss further, but result in a few rolls extra of some width or another.

3 0

3 years ago

A locker combination consists of two nonzero digits, and each combination consists of different digits. Event A is defined as ch

Troyanec [42]

The correct answer is option B which is P ( A|B) will be ( 4 / 9 ).

<h3>What is probability?</h3>

Probability is defined as the ratio of the number of favorable outcomes to the total number of outcomes in other words the probability is the number that shows the happening of the event.

Given that:-

A locker combination consists of two nonzero digits, and each combination consists of different digits. Event A is defined as choosing an odd number as the first digit, and event B is defined as choosing an odd number as the second digit.

The total sample will have 9 numbers

S = { 1,2,3,4,5,6,7,8,9} = 9

Even Number = { 2,4,6,8} = 4

Odd Number = { 1,3,5,7,9} = 5

P ( A ) = ( 4 / 9 )

P ( B ) = ( 5 / 9 )

The probability will be calculated as:-

P( A:B ) = $\dfrac{P(A)\times P(B)}{P(B)}$