Answer: S<\-2
Hope i was some help.
Step-by-step explanation: sorry I can’t put the right sign my keybored won’t let me but you know what it stands for.
3s+6s</-5(s+2)
start off with -5(s+2) you multiply -5 with s and it is -5s then you do the same for +2 take -5 and multiply by +2 pos times a neg is always a neg so it’s -10.
3s+6<\-5s-10
So you have to get rid of the -5s so your going to do the inverse which is add 5 to -5 and it will get rid of -5s but then you have to add 5 to 3s and that will be 8s.
8s+6</-10
Now your going to get rid of the +6 and to do that you do the inverse you subtract 6 and it will get rid of it now you have to do the same for -10 so you will subtract 6 to -10 and that will equal -16.
Now you have to divide!
8s/8 </ -16/8
And it should equal s <\-2
Answer:
(6x+1)9x-8)=0
Step-by-step explanation:
Answer:
12.12
Step-by-step explanation:
the formula to find x in this case would be:
______
x=√14^2-7^2
x=√c^2﹣a^2=√14^2﹣7^2≈12.12436
<h2>
Answer:</h2>
- Trip to work has rate: 24 mph
- Trip back to home has rate: 18 mph
- Distance to work is: 480 m
<h2>
Step-by-step explanation:</h2>
We know that speed is defined as the ratio of distance to time.
i.e.
Let the distance traveled to work be: x m.
Now, while going to work it takes a person 20 minutes.
This means that the speed of the person while going to work is:
Also, the time taken to come back home is: 30 minutes.
This means that the speed of person while riding to home is:
Also, it is given that the rate back is 8 mph slower than the trip to work.
This means that:
i.e.
Hence, the distance to work is: 480 m.
Also, the rate while going to work is:
and the trip back to home is covered with the speed:
