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erastovalidia [21]
3 years ago
9

HURRY!! WILL MARK BRAINLIEST!!

Mathematics
1 answer:
Alisiya [41]3 years ago
6 0

Answer:

2, the second number line.

Step-by-step explanation:

-1 x 1/2 = -0.5

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The number you are looking for is 995
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What is 7/8 divided by 11/16
Igoryamba
1.27 repeated is the answer
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Read 2 more answers
Y=4x-6 and passes through point 8,12
umka2103 [35]

Answer:

Slope of required line if both lines are parallel: y=4x-20

Slope of required line if both lines are perpendicular: y=-1/4x+14

Step-by-step explanation:

We need to find equation of line while we are given another line having equation y=4x-6 and passes through point (8,12)

<u><em>Note: Since it is not given if the required line is parallel or perpendicular to the given line. I will solve for both cases.</em></u>

If Both lines are parallel the equation of new line will be:

We need to find slope and y-intercept to write equation of new line.

When lines are parallel there slopes are same

So, slope of given line y=4x-6 is 4 (Compare with general equation y=mx+b, m is slope so m=4)

Slope of new line is: m=4

Now finding y-intercept

Using slope m=4 and point (8,12) we can find y-intercept

y=mx+b\\12=4(8)+b\\12=32+b\\b=12-32\\b=-20

y-intercept of new line is: b=-20

Equation of required line having slope m=4 and y-intercept b=-20 is

y=mx+b\\y=4x-20

If Both lines are perpendicular the equation of new line will be:

We need to find slope and y-intercept to write equation of new line.

When lines are perpendicular there slopes are opposite of each other

So, slope of given line y=4x-6 is 4 (Compare with general equation y=mx+b, m is slope so m=4)

Slope of new line is: m=-1/4

Now finding y-intercept

Using slope m=-1/4 and point (8,12) we can find y-intercept

y=mx+b\\12=-\frac{1}{4} (8)+b\\12=-2+b\\b=12+2\\b=14

y-intercept of new line is: b=14

Equation of required line having slope m=-1/4 and y-intercept b=14 is

y=mx+b\\y=-\frac{1}{4} x+14

8 0
3 years ago
Multiply r^2+7r+10/3 by 3r-30/r^2-5r-50
olga_2 [115]
<span>(r^2+7r+10/3) * (3r-30/r^2-5r-50)
1/3(3r^2+21r+10) x 3(r-10)/(r^2-5r-50)
(3r^2+21r+10)x(r-10)/(r^2-10r+5r-50)
(3r^2+21r+10)x(r-10)/(r-10)(r+5)
3r^2+21r+10/(r+5)



</span>
5 0
3 years ago
What is the equation of a line with slope -1/2 passing through (-5,4)?
elena-14-01-66 [18.8K]
For this question you need to use what's called point-slope form. It's named this way because you can use it if you have both the slope and a point at which the line passes through. That said, the equation is as follows:

y - y1 = m(x - x1)

Both y1 and x1 represent the y and x coordinates you are given in the question. Also, m represents the slope of the line that you are given. Knowing this, our equation now looks like this:

y - 4 = -0.5(x - (-5))

And now simplify:

y - 4 = -0.5(x + 5)
y - 4 = -0.5x - 2.5

y = -0.5x + 1.5
4 0
3 years ago
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