Please help on 10-15 I will give brainiest or thanks

Which ratio is equivalent to 4:32?

Morgarella [4.7K]

Answer:

1 : 8

Step-by-step explanation:

6 0

3 years ago

A local diner must build a wheelchair ramp to provide handicap access to the restaurant. Building codes require that a wheelchai

lozanna [386]

Answer:

A) 1/20

B) H = x/20

C) 9.5 in

Step-by-step explanation:

A) Slope is the ratio of rise to run, so is ...

slope = rise/run = (1 in)/(20 in)

slope = 1/20

__

B) The maximum height is 1/20 of the horizontal distance, so ...

H = (1/20)x

__

C) Using x=190 in the above formula, ...

H = (190 in)/20 = 9.5 in

The ramp will reach a height of 9.5 inches.

4 0

3 years ago

This cylinder has a volume of 121 cubic inches and a diameter of 4 inches.

iogann1982 [59]

12(pi)
diameter is 4, so radius should be 2
closest height to equal 12(pi) would be 0.96

7 0

3 years ago

Six measurements were made of the magnesium ion concentration (in parts per million, or ppm) in a city's municipal water supply,

NARA [144]

Answer:

The 98% confidence interval for the mean magnesium ion concentration is between 122 ppm and 220 ppm. As the lower bound of the interval is below 195, it is not reasonable to conclude that the mean magnesium ion concentration may be greater than 195

Step-by-step explanation:

The six measurements are:

202, 164, 157, 177, 113, 213

Sample mean:

Sum of all values divided by the number of values which is 6. So

$S_m = \frac{202+164+157+177+113+213}{6} = 171$

Sample standard deviation:

Square root of the difference squared between each value and the mean, and divided by 1 subtracted by the sample size. So

$s = \sqrt{\frac{(202-171)^2+(164-171)^2+(157-171)^2+(177-171)^2+(113-171)^2+(213-171)^2}{5}} = 35.69$

Confidence interval

We have the standard deviation for the sample, which means that the t-distribution will be used to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 6 - 1 = 5

98% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 5 degrees of freedom(y-axis) and a confidence level of $1 - \frac{1 - 0.98}{2} = 0.99$ . So we have T = 3.365

The margin of error is:

$M = T\frac{s}{\sqrt{n}} = 3.365\frac{35.69}{\sqrt{6}} = 49$

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 171 - 49 = 122 ppm

The upper end of the interval is the sample mean added to M. So it is 171 + 49 = 220 ppm

The 98% confidence interval for the mean magnesium ion concentration is between 122 ppm and 220 ppm. As the lower bound of the interval is below 195, it is not reasonable to conclude that the mean magnesium ion concentration may be greater than 195

8 0

3 years ago

the length.of a hypotenuse of a right triangle is 32 inches and the length of one of the lrgs is 18 inches. what is the length,

Elza [17]

Let: hypotenuse = a , known leg = b , unknown leg = c
According to Pythagoras' Theorem: $a^{2} = b^{2} + c^{2}$
   $c^{2} = a^{2} - b^{2}$
   $c^{2} = (32 inches)^{2} - (18 inches)^{2}$
c = $\sqrt{(32 inches)^{2} - (18 inches)^{2}}$
c = 3.74 inches

∴ the length of the hypotenuse to 1d.p. ≈ 3.74 inches

6 0

3 years ago