Answer:
The formula is F = P(1 + interest percent)^n
Here,
p =8000 dollar
interest percent =5.5% = (5.5/12)/100 =0.004583 (compounded monthly)
n =7 x 12 =84 (compounded monthly)
=> Mark's account balance after 7 years
F = 8000*(1+0.004583)^84 =11746.2503 dollar
1 + 3i, - sqrt 10 would be the other two answers
Using the normal distribution, it is found that there is a 0.2776 = 27.76% probability that the life span of the monitor will be more than 20,179 hours.
<h3>Normal Probability Distribution</h3>
The z-score of a measure X of a normally distributed variable with mean
and standard deviation
is given by:

- The z-score measures how many standard deviations the measure is above or below the mean.
- Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.
The mean and the standard deviation are given, respectively, by:

The probability that the life span of the monitor will be more than 20,179 hours is <u>one subtracted by the p-value of Z when X = 20179</u>, hence:


Z = 0.59.
Z = 0.59 has a p-value of 0.7224.
1 - 0.7224 = 0.2776.
0.2776 = 27.76% probability that the life span of the monitor will be more than 20,179 hours.
More can be learned about the normal distribution at brainly.com/question/24663213
#SPJ1