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german
3 years ago
6

If the racetrack publishes that the odds in favor of a horse winning a race are 5 to 9, what is probability that the horse will

not win the race?
Mathematics
2 answers:
crimeas [40]3 years ago
5 0
I divided 5 by 9 and multiplied it by 100 to get the percentage for the probability the horse will win. I got 55.55%. I subtracted 55.55 from 100 and got 44.45% chance of not winning the race.
LUCKY_DIMON [66]3 years ago
3 0

Answer: \dfrac{9}{14}

Step-by-step explanation:

We know that , In probability the odds for an event is the ratio of the favorable outcomes to the unfavorable outcomes.

We are given that ,

The racetrack publishes that the odds in favor of a horse winning a race are 5 to 9 .

i.e. favorable outcomes for horse winning a race = 5

i.e.  unfavorable outcomes for horse winning a race = 9

Now , Total outcomes = favorable outcomes+  unfavorable outcomes

= 5+9 = 14

Then, the probability that the horse will not win the race=\dfrac{\text{Unfavorable outcomes}}{\text{Total outcomes}}

=\dfrac{9}{14}

Hence, the probability that the horse will not win the race =\dfrac{9}{14}

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