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kap26 [50]
3 years ago
15

5/8 + 3/4 | -2/3 - 5/6

Mathematics
1 answer:
JulsSmile [24]3 years ago
8 0

Answer:

- \frac{11}{12}

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Which will result in a difference of squares?
SIZIF [17.4K]

Answer:

The expression which will result in difference of two squares is:

 (–7x + 4)·(–7x – 4)

Step-by-step explanation:

We know that the formula of the type:

(a-b)(a+b)=a²-b²

i.e. it is a difference of two square quantities. (a^2 and b^2)

since,

a= -7x , b=4

(-7x+4)(-7x-4)= (-7x)² - (4)²

=(7x)² - 4²

So the expression is a difference of two square quantities:

(7x)² and (4)²

Hence the answer is (–7x + 4)·(–7x – 4)....

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3 years ago
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4 years ago
Solve in standard form: 2x +y=-2
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Step-by-step explanation:

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3 years ago
Question 7 Essay Worth 5 points)
TEA [102]

Answer:This is a tricky question that Reina and Sam are multiplying (84)5 (73)9 and their work are (84)5 (73)9 = 84 + 573 + 9 = 89712 Reina's (84)5 (73)9 = 84-573-9 = 820727 Sam's Actually they are doing or multiplying using exponents. Reina's work (8*)s(7³)º=8*+5+ 73+9= 8° 712 This is incorrect because she added exponents instead of multiplying exponents Sams work (8*)5 (7³)º=84x5 73x9= 820 727 This is correct because Sam multiplied exponents correctly Exponents are multiplied not added.

7 0
3 years ago
1) The perimeter of a rectangular classroom floor is 90 feet. The length of the floor is twice the
lana [24]

Answer: The equation would NOT help us solve for the length and width of the classroom is "x + 2y = 90".

Step-by-step explanation:

Let y be the width of the rectangular classroom floor and x be the length of the rectangular classroom floor .

Given ,

The perimeter of a rectangular classroom floor is 90 feet.

The length of the floor is twice the  width.

i.e. Length =2 (width)

i.e. x= 2y ..(i)

Also, perimeter = 2(length+width)

i.e. 2(x+y)=90\\\\\Rightarrow\ 2x+2y=90

When we put value of x from (i), we get

2(2y) + 2y = 90

Hence, the equation would NOT help us solve for the length and width of the classroom is "x + 2y = 90".

8 0
3 years ago
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