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elixir [45]
4 years ago
11

Teddy was having trouble fitting into his clothes due to weight gain. In January, he weighed 180 lbs 6 oz. He gained 3 lbs 9 oz,

5 lbs 12 oz, and 6 lbs 11oz in the next three months. How much does Teddy weigh now?

Mathematics
1 answer:
barxatty [35]4 years ago
7 0
He weighs 196 lbs and 6 ounces. if you add the pounds (180 to 3, 5, 6)you get 194. then you add he ounces, and remember that there are 16 ounces in a pound and 8 ounces in a cup, (6 to 9, 12, 11) you get 2lbs and 6 ounces. then you add the 2 extra pounds to the 194 and you get, all together, 196 lbs and 6 ounces.
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In a large section of a statistics​ class, the points for the final exam are normally​ distributed, with a mean of 71 and a stan
kumpel [21]

Answer:

The lowest score on the final exam that would qualify a student for an​ A is 80.

The lowest score on the final exam that would qualify a student for a B is 74.68.

The lowest score on the final exam that would qualify a student for a C is 67.33.

The lowest score on the final exam that would qualify a student for a​ D is 62.

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Mean of 71 and a standard deviation of 7.

This means that \mu = 71, \sigma = 7

Grades are assigned such that the top​ 10% receive​ A's, the next​ 20% received​ B's, the middle​ 40% receive​ C's, the next​ 20% receive​ D's, and the bottom​ 10% receive​ F's.

This means that:

90th percentile and above: A

70th percentile and below 90th: B

30th percentile to the 70th percentile: C

10th percentile to the 30th: D

Lowest score for an A:

Top 10% receive A, which means that the lowest score that would qualify a student for an A is the 100 - 10 = 90th percentile, which is X when Z has a pvalue of 0.9, so X when Z = 1.28.

Z = \frac{X - \mu}{\sigma}

1.28 = \frac{X - 71}{7}

X - 71 = 7*1.28

X = 80

The lowest score on the final exam that would qualify a student for an​ A is 80.

Lowest score for a B:

70th percentile, which is X when Z has a pvalue of 0.7, so X when Z = 0.525.

Z = \frac{X - \mu}{\sigma}

0.525 = \frac{X - 71}{7}

X - 71 = 7*0.525

X = 74.68

The lowest score on the final exam that would qualify a student for a B is 74.68.

Lowest score for a C:

30th percentile, which is X when Z has a pvalue of 0.3, so X when Z = -0.525.

Z = \frac{X - \mu}{\sigma}

-0.525 = \frac{X - 71}{7}

X - 71 = 7*(-0.525)

X = 67.33

The lowest score on the final exam that would qualify a student for a C is 67.33.

Lowest score for a D:

10th percentile, which is X when Z has a pvalue of 0.1, so X when Z = -1.28.

Z = \frac{X - \mu}{\sigma}

-1.28 = \frac{X - 71}{7}

X - 71 = 7*(-1.28)

X = 62

The lowest score on the final exam that would qualify a student for a​ D is 62.

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Answer:

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Step-by-step explanation:

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On the set of axes below, draw the graph of y=x^2-4x-1
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9514 1404 393

Answer:

  axis of symmetry: x = 2

  see below for a graph

Step-by-step explanation:

You can complete the square to put the equation in vertex form.

  y = (x^2 -4x +4) -1 -4

  y = (x -2)^2 -5 . . . . . . vertex is (2, -5)

The equation of the axis of symmetry is the equation of the vertical line through the vertex:

  x = 2 . . . . . axis of symmetry

__

Points on the graph are easily found by using integer values on either side of x=2. Points on one side of the axis of symmetry are mirrored on the other side of it.

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