Answer:
whats your questionnnnn..???
Step-by-step explanation:
Answer:
1)
Ratio is 1:1.
2)
The required number is:
![5^4\times 50](https://tex.z-dn.net/?f=5%5E4%5Ctimes%2050)
Step-by-step explanation:
1)
Let us consider that Cecilia's has a total of 'x' CDs
and let 'y' represent the number of Jazz CDs.
Now we are given information that:
1/5 of her Jazz CDs represents 1/10 of all her CDs.
i.e. ![\dfrac{1}{5}y=\dfrac{1}{10}x\\\\y=\dfrac{5}{10}x\\\\y=\dfrac{1}{2}x](https://tex.z-dn.net/?f=%5Cdfrac%7B1%7D%7B5%7Dy%3D%5Cdfrac%7B1%7D%7B10%7Dx%5C%5C%5C%5Cy%3D%5Cdfrac%7B5%7D%7B10%7Dx%5C%5C%5C%5Cy%3D%5Cdfrac%7B1%7D%7B2%7Dx)
i.e. the Jazz CDs are half of the total CDs.
Hence, the number of Non-Jazz CDs(z)
= ![x-\dfrac{x}{2}\\\\=\dfrac{x}{2}](https://tex.z-dn.net/?f=x-%5Cdfrac%7Bx%7D%7B2%7D%5C%5C%5C%5C%3D%5Cdfrac%7Bx%7D%7B2%7D)
Hence, the ratio of Jazz to Non-Jazz CDs
![=\dfrac{y}{z}\\\\=\dfrac{\dfrac{x}{2}}{\dfrac{x}{2}}\\\\=\dfrac{1}{1}](https://tex.z-dn.net/?f=%3D%5Cdfrac%7By%7D%7Bz%7D%5C%5C%5C%5C%3D%5Cdfrac%7B%5Cdfrac%7Bx%7D%7B2%7D%7D%7B%5Cdfrac%7Bx%7D%7B2%7D%7D%5C%5C%5C%5C%3D%5Cdfrac%7B1%7D%7B1%7D)
Hence, the required Ratio is 1:1.
2)
How would you change
to a number times 25?
We will find the number by dividing the quantity
by 25 to find the required number.
i.e. ![\dfrac{5^6\times 50}{25}=\dfrac{5^6\times 50}{5^2}=5^{6-2}\times 50=5^4\times 50](https://tex.z-dn.net/?f=%5Cdfrac%7B5%5E6%5Ctimes%2050%7D%7B25%7D%3D%5Cdfrac%7B5%5E6%5Ctimes%2050%7D%7B5%5E2%7D%3D5%5E%7B6-2%7D%5Ctimes%2050%3D5%5E4%5Ctimes%2050)
Hence the required number is:
![5^4\times 50](https://tex.z-dn.net/?f=5%5E4%5Ctimes%2050)
Answer:
yo what?
Step-by-step explanation:
the health is this you awnser le ? I uh what?
Answer:
"13 / 204 ; No, they are dependent events
"
Step-by-step explanation:
The probability of getting a club at first throw is simply total number of clubs divided by total number of cards in the deck.
Total clubs is 13
Total cards in deck is 52
Hence, P(clubs) = ![\frac{13}{52}](https://tex.z-dn.net/?f=%5Cfrac%7B13%7D%7B52%7D)
<em>Since the first card IS NOT replaced, the deck has now 51 cards. We want probability of diamond. There are still 13 diamonds, so probability of diamond now would be 13/51</em>
<em />
Hence, Probability that first card is a club and the second card is a diamond should be 13/52 MULTIPLIED by 13/51
P(1st Club, 2nd Diamond) = ![\frac{13}{52}*\frac{13}{51}=\frac{13}{204}](https://tex.z-dn.net/?f=%5Cfrac%7B13%7D%7B52%7D%2A%5Cfrac%7B13%7D%7B51%7D%3D%5Cfrac%7B13%7D%7B204%7D)
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<u>Note: </u>They are dependent events since we are calculating probability without replacement. The first draw affected the total number of cards in the 2nd draw.
2nd answer choice is right.
Answer: Yes
Step-by-step explanation:
15/60 divided both by 15:
15/15=1 and 60/15=4