Linear equations are equations that have constant slopes
The linear equation that represents the table is (a) y = 7x +4
<h3>How to determine the linear equation</h3>
Start by calculating the slope (m) using:
So, we have:
Simplify
The equation is then calculated as:
So, we have:
Open the brackets
Hence, the linear equation that represents the table is (a) y = 7x +4
Read more about linear equations at:
brainly.com/question/14323743
Answer:
Step-by-step explanation:
x = -10/3
x = -3 1/3
The answer is 12. 3/4 and 1/16 have a common denominator of 16. multiply 3/4 by 4 and get 12/16. divide that by 1/16 and get 12/1 making the answer 12.
Answer:
15/14
Step-by-step explanation:
Answer: 6(x²-4x+4-4)+1=0, 6(x-2)²-24+1=0, 6(x-2)²=23, x-2=±√(23/6), x=2±√(23/6)=2±1.95789, so x=3.95789 or 0.04211 approx. these are the zeros.
step by step explanation:
\boxed{\boxed{\dfrac{12+\sqrt{138}}{6},\ \dfrac{12-\sqrt{138}}{6}}}
Solution-
The quadratic function is,
6x^2-24x + 1
a = 6, b = -24, c = 1
x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}
=\dfrac{-(-24)\pm \sqrt{-24^2-4\cdot 6\cdot 1}}{2\cdot 6}
=\dfrac{24\pm \sqrt{576-24}}{12}
=\dfrac{24\pm \sqrt{552}}{12}
=\dfrac{24\pm 2\sqrt{138}}{12}
=\dfrac{12\pm \sqrt{138}}{6}
=\dfrac{12+\sqrt{138}}{6},\ \dfrac{12-\sqrt{138}}{6}