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wlad13 [49]
3 years ago
10

What are the zeros of the quadratic function f (x) = 2x^2 -10x-3?

Mathematics
1 answer:
emmainna [20.7K]3 years ago
6 0

Answer:

x=2.5+sqrt(300)/4, 2.5-sqrt(300)/4

Step-by-step explanation:

1. Need to factor or can use the quadratic formula

2x^2-10x-3=0

a=2, b=-10, c=-3

[-b+-sqrt(b^2-4*a*c)]/(2*a)

[10+-sqrt(100-4*(-200)]/4

[10+- sqrt(300)]/4

x=2.5+sqrt(300)/4, 2.5-sqrt(300)/4

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For the trinomial x^2-11x+10 determine if the factors of c will will be both positive, both negative, or opposite signs.
IrinaVladis [17]

Answer:

Two negatives

Step-by-step explanation:

I'm assuming by 'factors of c' you mean factors of the last term. For the entire trinomial, we know that there are two negative signs. To be able to get a negative 11x and then a positive 10, we would need two negatives, since two negatives equal a positive. Hope that helps!

5 0
3 years ago
PLEEAAAASE help <br> if a+1 is divisible by 3 prove that 4+7a is divisible by 3 too
Lemur [1.5K]

Answer:

Given a is 5

Step-by-step explanation:

I. Given a is 5

= a + 1

= 5 + 1

= 6

6 is divisible by 3 => true

II. Find 4 + 7a value

  = 4 + 7(5)

  = 4 + 35

  = 39

39 is divisible by 3 => true

III. Prove by

6 ÷ 3 = 3

39 ÷ 3 = 13

Hope that help :)

3 0
3 years ago
Workout this equation<br> X(x+2)(x+4)
rewona [7]

Answer:

x^3  <-- exponent, x to the power of three

Explanation:

x(x+2)(x+4)

=(x(x+2))(x+4)

=(x(x+2))(x)+(x(x+2))(4)

=x^3+2x^2+4x^2+8x

=x^3+6x^2+8x

4 0
3 years ago
Read 2 more answers
How to find midpoint of (-42,-53) and (28, -19)
VikaD [51]
Mid point  =  ( 1/2 the sum of x coordinates) ,  ( 1/2 sum of y coordinates)

=  (-42+28)/2 .  ( -53 - 19) / 2

= ( -7, -36) Answer
5 0
3 years ago
2.
EleoNora [17]

Answer:

yes

Step-by-step explanation:

because i need points.......................................................

7 0
3 years ago
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