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nikitadnepr [17]
3 years ago
15

How to find midpoint of (-42,-53) and (28, -19)

Mathematics
1 answer:
VikaD [51]3 years ago
5 0
Mid point  =  ( 1/2 the sum of x coordinates) ,  ( 1/2 sum of y coordinates)

=  (-42+28)/2 .  ( -53 - 19) / 2

= ( -7, -36) Answer
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How is the building code for using asphalt shingles on a roof related to the definition of slope?
iren2701 [21]
Because they're both slant like and they both is like you're going down a hill
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3 years ago
Edi plays 1/4 of a song in 1/8 of a minute how many minutes will he need to play a full song
Neporo4naja [7]

Answer:

Let's see what to do buddy...

Step-by-step explanation:

first \:  \:  \:  \frac{1}{4} \:  \:  \:of \:a \: song \: needs \:  \frac{1}{8} \:  \: minute. \\  \\ second \:  \:  \:  \frac{1}{4} \:  \: of \: a \: song \: needs \:  \frac{1}{8} \: minute \: too. \\  \\ also \: the \: third \: and \: fourth \:  \:  \:  \frac{1}{4} \:  \:  \:  of  \: a \: song \: need \:  \frac{1}{8} \: minute \: . \\  \\ so \: we \: have \: completly \: have \: 4 \times  \frac{1}{8} \\  \\ which \: means \: edi \: needs \: 4 \times  \frac{1}{8}  =  \frac{4}{8} =  \frac{1}{2} \:  minute \: to \: play \: all \: the \: song.

And we're done.

Thanks for watching buddy good luck.

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3 0
3 years ago
(-2.66) multiplied by (18.44)
Stells [14]

Answer:

I think the answer you're looking for is -49.05

(longer version: -49.0504)

4 0
3 years ago
Service calls arriving at an electric company follow a Poisson distribution with an average arrival rate of 5656 per hour. Find
liberstina [14]

Answer:

The average number of service calls in a 15-minute period is of 14, with a standard deviation of 3.74.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given interval. The variance is the same as the mean.

Average rate of 56 calls per hour:

This means that \mu = 56n, in which n is the number of hours.

Find the average and standard deviation of the number of service calls in a 15-minute period.

15 minute is one fourth of a hour, which means that n = \frac{1}{4}. So

\mu = 56n = \frac{56}{4} = 14

The variance is also 14, which means that the standard deviation is \sqrt{14} = 3.74

The average number of service calls in a 15-minute period is of 14, with a standard deviation of 3.74.

4 0
3 years ago
10 kids are randomly grouped into an A team with five kids and a B team with five kids. Each grouping is equally likely. (a) Wha
nikitadnepr [17]

Answer:

I think B is 1/5. I think C is 1/2.

4 0
3 years ago
Read 2 more answers
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