Ask question

Ask question

All categories

nikitadnepr [17]

3 years ago

15

How to find midpoint of (-42,-53) and (28, -19)

1 answer:

VikaD [51]3 years ago

5 0

Mid point = ( 1/2 the sum of x coordinates) , ( 1/2 sum of y coordinates)

= (-42+28)/2 . ( -53 - 19) / 2

= ( -7, -36) Answer

You might be interested in

How is the building code for using asphalt shingles on a roof related to the definition of slope?

iren2701 [21]

Because they're both slant like and they both is like you're going down a hill

8 0

3 years ago

Edi plays 1/4 of a song in 1/8 of a minute how many minutes will he need to play a full song

Neporo4naja [7]

Answer:

Let's see what to do buddy...

Step-by-step explanation:

$first \: \: \: \frac{1}{4} \: \: \:of \:a \: song \: needs \: \frac{1}{8} \: \: minute. \\ \\ second \: \: \: \frac{1}{4} \: \: of \: a \: song \: needs \: \frac{1}{8} \: minute \: too. \\ \\ also \: the \: third \: and \: fourth \: \: \: \frac{1}{4} \: \: \: of \: a \: song \: need \: \frac{1}{8} \: minute \: . \\ \\ so \: we \: have \: completly \: have \: 4 \times \frac{1}{8} \\ \\ which \: means \: edi \: needs \: 4 \times \frac{1}{8} = \frac{4}{8} = \frac{1}{2} \: minute \: to \: play \: all \: the \: song.$

And we're done.

Thanks for watching buddy good luck.

♥️♥️♥️♥️♥️

3 0

3 years ago

(-2.66) multiplied by (18.44)

Stells [14]

Answer:

I think the answer you're looking for is -49.05

(longer version: -49.0504)

4 0

3 years ago

Service calls arriving at an electric company follow a Poisson distribution with an average arrival rate of 5656 per hour. Find

liberstina [14]

Answer:

The average number of service calls in a 15-minute period is of 14, with a standard deviation of 3.74.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given interval. The variance is the same as the mean.

Average rate of 56 calls per hour:

This means that $\mu = 56n$ , in which n is the number of hours.

Find the average and standard deviation of the number of service calls in a 15-minute period.

15 minute is one fourth of a hour, which means that $n = \frac{1}{4}$ . So

$\mu = 56n = \frac{56}{4} = 14$

The variance is also 14, which means that the standard deviation is $\sqrt{14} = 3.74$

The average number of service calls in a 15-minute period is of 14, with a standard deviation of 3.74.

4 0

3 years ago

10 kids are randomly grouped into an A team with five kids and a B team with five kids. Each grouping is equally likely. (a) Wha

nikitadnepr [17]

Answer:

I think B is 1/5. I think C is 1/2.

4 0

3 years ago

Read 2 more answers