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3 years ago

Which pair of transformations could map AABC to AA'B'C', such that the triangles are similar but

Mathematics

1 answer:

nordsb [41]3 years ago

8 0

Answer:

a dilation and a rotation

Step-by-step explanation:i got it on my iready

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HELP PLEASE ASAP:

VashaNatasha [74]

The average rate of change, of the function, between the intervals, x = 2 to x = 6 is: 180.

<h3>What is the Average Rate of Change of a Function?</h3>

Average rate of change = $\frac{f(b) - f(a)}{b - a}$ .

Given the function, $f(x)= 3^x + 25$ ,

The average rate of change using the intervals of, x = 2 to x = 6 would be solved as shown below:

a = 2

b = 6

f(a) = $f(2)= 3^2 + 25$ = 34

f(b) = $f(6)= 3^6 + 25$ = 754

Average rate of change = $\frac{754 - 34}{6 - 2} = \frac{720}{4}$

Average rate of change = 180

Therefore, the average rate of change, of the function, between the intervals, x = 2 to x = 6 is: 180.

Learn more about average rate of change on:

brainly.com/question/8728504

5 0

2 years ago

Sin Z=0.6561 <br> A 48 degrees<br> B 41 degrees<br> C 53 degrees<br> D 0.01 degrees

serg [7]

The answer would be b

8 0

3 years ago

Find the product 6,372×75

saw5 [17]

477900 there you go use a calculator next time ;)

7 0

3 years ago

Read 2 more answers

Assume that it costs Apple approximately E(x) 25,600 + 100x + 0.012 dollars to manufacture x 32GB iPods in a day. (a) The averag

uranmaximum [27]

Answer:

(a) $C'(x)=\dfrac{x^2-2560000}{x^2}$

(b)x=1600, Minimum Average Cost Per iPod=$132

The result, C''(1600) is positive, which means that the average cost is Concave up at the critical point, and the critical point is a minimum.

Step-by-step explanation:

Given that it costs Apple approximately $ C(x) to manufacture x 32GB iPods in a day, where:

$C(x)=25,600+100x+0.01x^2$

(a)The average cost per iPod when they manufacture x iPods in a day is given by:

$Cost \:Per \:iPod=\dfrac{C(x)}{x} =\dfrac{25,600+100x+0.01x^2}{x}$

The average cost per iPod is therefore:

$C'(x)=\dfrac{x^2-2560000}{x^2}$

(b)To minimize average cost of x iPods per day, we set the average cost per iPod=0 and solve for x.

$C'(x)=\dfrac{x^2-2560000}{x^2}=0\\x^2-2560000=0\\x^2=2560000\\x=\sqrt{2560000}=1600$

The resulting minimum average cost (at x=1600) is given as:

$Cost \:Per \:iPod=\dfrac{C(x)}{x} =\dfrac{25,600+100x+0.01x^2}{x}\\\dfrac{25,600+100(1600)+0.01(1600)^2}{1600}\\=\$132$

<u>Second derivative test</u>

(c)The answer above is a critical point for the average cost function. To show it is a minimum, we calculate the second derivative of the average cost function.

$C''(x)=\dfrac{5120000}{x^3}$

At the critical point, x=1600

$C''(1600)=\dfrac{5120000}{1600^3}=0.00125$

The result, C''(1600) is positive, which means that the average cost is Concave up at the critical point, and the critical point is a minimum.

3 0

3 years ago

If f(x)=(x+6)(x−3)/(x−2), then calculate f(5). Round answers to two decimal places.

Marina CMI [18]

Step-by-step explanation:

f(5)=(5+6)(5-3)/(5-2)

=11(2)/3

=22/3

=7.33

5 0

3 years ago