Answer:
0.4054 = 40.54% probability of selecting a black sock on the second draw given that a black sock was selected on the first draw
Step-by-step explanation:
Conditional Probability
We use the conditional probability formula to solve this question. It is
In which
P(B|A) is the probability of event B happening, given that A happened.
is the probability of both A and B happening.
P(A) is the probability of A happening.
In this question:
Event A: Black sock on the first draw.
Event B: Black sock on the second draw.
The probability of selecting a black sock on the first draw is 8/19.
This means that
Black socks on both draws:
The probability of selecting two black socks is 120/703
This means that
What is the probability of selecting a black sock on the second draw given that a black sock was selected on the first draw?
0.4054 = 40.54% probability of selecting a black sock on the second draw given that a black sock was selected on the first draw
A=p(1+i/m)^mn
A=734×(1+0.1÷2)^(2×5)=1,195.61
Then calculate the interest
I=A-p
I=1,195.61−734=461.61
Compare to . Then in applying the LCT, we have
Because this limit is finite, both
and
behave the same way. The second series diverges, so
is divergent.
Answer:
GOOD!
Step-by-step explanation:
Answer:
<em>(5x−3)(x−3)</em>
Step-by-step explanation:
For a polynomial of the form
ax2+bx+c, rewrite the middle term as a sum of two terms whose product is
a⋅c=5⋅9=45 and whose sum is b=−18.
5x2−3x−15x+9
Factor out the greatest common factor from each group.
x(5x−3)−3(5x−3)
Factor the polynomial by factoring out the greatest common factor, 5x−3.
(5x−3)(x−3)