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maks197457 [2]
2 years ago
6

Does the frequency distribution appear to have a normal distribution using a strict interpretation of the relevant​ criteria?Tem

perature(f)35-39,40-44,45-49,50-54
Frequency 3,0,4,15
Temperature(f)55-59,60-64,65-69
Frequency 7,5,1

Does the frequency distribution appear to have a normal​ distribution?
A. All these requirements are met
B.no, this distribution does not appear to be normal
C. No frequencies do not decrease from the maximum frequency to a low frequencies

Mathematics
1 answer:
Xelga [282]2 years ago
3 0

Answer:

B. No, this distribution does not appear to be normal

Step-by-step explanation:

Hello!

To observe what shape the data takes, it is best to make a graph. For me, the best type of graph is a histogram.

The first step to take is to calculate the classmark`for each of the given temperature intervals. Each class mark will be the midpoint of each bar.

As you can see in the graphic (2nd attachment) there are no values of frequency for the interval [40-44] and the rest of the data show asymmetry skewed to the left. Just because one of the intervals doesn't have an observed frequency is enough to say that these values do not meet the requirements to have a normal distribution.

The answer is B.

I hope it helps!

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Semenov [28]

Answer:

The answers are \frac{2}{5}, \frac{1}{4}, \frac{1}{10}, \frac{5}{2}, \frac{5}{8}, \frac{4}{1}, \frac{8}{5}, and \frac{10}{1}.

Step-by-step explanation:

Proportions are fractions that can be made by using the given numbers, which in this case are 2, 5, 8, and 20. Let's pair each one with the other three and then simplify if possible.

First, let's begin with 2:

\frac{2}{5} = \frac{2}{5}

\frac{2}{8} = \frac{1}{4}

\frac{2}{20} = \frac{1}{10}

Then, let's do 5:

\frac{5}{2} = \frac{5}{2}

\frac{5}{8} = \frac{5}{8}

\frac{5}{20} = \frac{1}{4}

Note that we already have \frac{1}{4}, so we do not need to include an additional one.

Now, let us do 8:

\frac{8}{2} = \frac{4}{1}

\frac{8}{5} = \frac{8}{5}

\frac{8}{20} = \frac{2}{5}

See how we already have \frac{2}{5}, so we won't have to include that as well.

Finally, let's do 20:

\frac{20}{2} = \frac{10}{1}

\frac{20}{5} = \frac{4}{1}

\frac{20}{8} = \frac{5}{2}

Now see that we already have both \frac{4}{1} and \frac{5}{2}, so we won't have to include both of them, as they are both extras.

Hence, the answers are \frac{2}{5}, \frac{1}{4}, \frac{1}{10}, \frac{5}{2}, \frac{5}{8}, \frac{4}{1}, \frac{8}{5}, and \frac{10}{1}.

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3 years ago
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Svetradugi [14.3K]
Since 4 is between 2 & 5 you input it into the middle equation.

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Answer:

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Step-by-step explanation:

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3 years ago
Find the value of n:<br> <img src="https://tex.z-dn.net/?f=%5Cfrac%7Bn%7D%7B11%7D%20%3D%20%5Cfrac%7B3.5%7D%7B7%7D" id="TexFormul
EastWind [94]

The value of n from the given expression is 5.5

<h3>Solution to linear equation and fractions</h3>

Fractions are expression written as a ratio of two integers. The linear equation on the other hand has a leading degree of 1.

Given the equation below;

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Simplify to have

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Cross multiply the given result to have:

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Swap

2n = 11

Divide both sides by 2 to have;

2n/2 = 11/2

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Hence the value of n from the given expression is 5.5

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