Does the frequency distribution appear to have a normal distribution using a strict interpretation of the relevant criteria?Tem
perature(f)35-39,40-44,45-49,50-54
Frequency 3,0,4,15
Temperature(f)55-59,60-64,65-69
Frequency 7,5,1
Does the frequency distribution appear to have a normal distribution?
A. All these requirements are met
B.no, this distribution does not appear to be normal
C. No frequencies do not decrease from the maximum frequency to a low frequencies
Frequency 3,0,4,15
Temperature(f)55-59,60-64,65-69
Frequency 7,5,1
Does the frequency distribution appear to have a normal distribution?
A. All these requirements are met
B.no, this distribution does not appear to be normal
C. No frequencies do not decrease from the maximum frequency to a low frequencies
1 answer:
Answer:
B. No, this distribution does not appear to be normal
Step-by-step explanation:
Hello!
To observe what shape the data takes, it is best to make a graph. For me, the best type of graph is a histogram.
The first step to take is to calculate the classmark`for each of the given temperature intervals. Each class mark will be the midpoint of each bar.
As you can see in the graphic (2nd attachment) there are no values of frequency for the interval [40-44] and the rest of the data show asymmetry skewed to the left. Just because one of the intervals doesn't have an observed frequency is enough to say that these values do not meet the requirements to have a normal distribution.
The answer is B.
I hope it helps!
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Answer:
The sum of the two numbers is 15
Step-by-step explanation:
Let the counting numbers be x and y.
Then we can write the following equations
x=4y.......1 (one is four times greater )
x(y)=36.....2 (the product of the two)
Putting equation 1 into equation 2, we get
4y(y)=36
Dividing through by 4,we get
Taking square root of both side, we obtain
y=3
Putting the value of y into equation , we get
x=4(3)=12
Hence the numbers are 3 and 12
Therefore the sum of the two numbers is 3+12=15