Does the frequency distribution appear to have a normal distribution using a strict interpretation of the relevant criteria?Tem
perature(f)35-39,40-44,45-49,50-54
Frequency 3,0,4,15
Temperature(f)55-59,60-64,65-69
Frequency 7,5,1
Does the frequency distribution appear to have a normal distribution?
A. All these requirements are met
B.no, this distribution does not appear to be normal
C. No frequencies do not decrease from the maximum frequency to a low frequencies
Frequency 3,0,4,15
Temperature(f)55-59,60-64,65-69
Frequency 7,5,1
Does the frequency distribution appear to have a normal distribution?
A. All these requirements are met
B.no, this distribution does not appear to be normal
C. No frequencies do not decrease from the maximum frequency to a low frequencies
1 answer:
Answer:
B. No, this distribution does not appear to be normal
Step-by-step explanation:
Hello!
To observe what shape the data takes, it is best to make a graph. For me, the best type of graph is a histogram.
The first step to take is to calculate the classmark`for each of the given temperature intervals. Each class mark will be the midpoint of each bar.
As you can see in the graphic (2nd attachment) there are no values of frequency for the interval [40-44] and the rest of the data show asymmetry skewed to the left. Just because one of the intervals doesn't have an observed frequency is enough to say that these values do not meet the requirements to have a normal distribution.
The answer is B.
I hope it helps!
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Answer:
4.01% probability that the battery will break down during the warranty period
Step-by-step explanation:
When the distribution is normal, we use the z-score formula.
In a set with mean and standard deviation
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question, we have that:
a. What is the probability that the battery will break down during the warranty period
Warranty of 2 years = 24 months. So this is the pvalue of Z when X = 24.
has a pvalue of 0.0401
4.01% probability that the battery will break down during the warranty period