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3 years ago

I need help on these ASAP !!!

Mathematics

2 answers:

liq [111]3 years ago

7 0

Answer:

IDK.

Step-by-step explanation:

Ask ur teacher for help.

I hope this helps u.

chubhunter [2.5K]3 years ago

3 0

Answer:

A) 102

C) 102

D) 78

Step-by-step explanation:

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If one batch needs 3/4 cups of oil. and she want to make 5 batches. how much would she need?

murzikaleks [220]

Answer:

3.75 cups of oil or 3 and 3/4 cups of oil

Step-by-step explanation:

Simple

1 batch=0.75 cups of oil(3/4)

5 Batch=? (Multiply by 5)

5 Batches=3.75 cups (or 3 3/4) of oil

5 0

2 years ago

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What is y-1 =2/3(x+3) in slope intercept form?

Elan Coil [88]

Answer:

The slope is just 2/3 and the y intercept is (0,3)

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2 years ago

Which of the following polygons has nine lines of symmetry?

anastassius [24]

So we know d. is out and that's all I got help wise sorry its not much..:)

3 0

3 years ago

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Write an equation of the line that passes through (18, 2) and is parallel to the line 3y−x=−12

miskamm [114]

keeping in mind that parallel lines have the same exact slope, hmmmm what's the slope of the line above anyway?

$\bf 3y-x=-12\implies 3y=x-12\implies y=\cfrac{x-12}{3}\implies y = \cfrac{x}{3}-\cfrac{12}{3} \\\\\\ y = \stackrel{\stackrel{m}{\downarrow }}{\cfrac{1}{3}}x-4\qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}$

so we're really looking for the equation of a line whose slope is 1/3 and runs through (18,2)

$\bf (\stackrel{x_1}{18}~,~\stackrel{y_1}{2})~\hspace{10em} \stackrel{slope}{m}\implies \cfrac{1}{3} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{2}=\stackrel{m}{\cfrac{1}{3}}(x-\stackrel{x_1}{18}) \\\\\\ y-2=\cfrac{1}{3}x-6\implies y=\cfrac{1}{3}x-4$

3 0

2 years ago

Una pelota sale disparada desde el nivel del suelo, con una velocidad de 40 m/s y un ángulo de elevación de 50°. a) Calcule la a

DedPeter [7]

Respuesta:

Los 47.85m

Explicación paso a paso:

Altura máxima = u²sin²Ф / 2g

Dado

velocidad u = 40 m / s

Ф = 50 °

g = 9,81 m / s²

Sustituir'

H = 40²sin²50 / 2 (9,81)

H = 1600 (0,7660) ² / 19,62

H = 1600 (0,5868) /19,62

H = 938,8096 / 19,62

H = 47,85 m

Por lo tanto, la altura máxima es de 47,85 m.

6 0

2 years ago