Given:
A figure of a right triangle and an altitude form the right angle vertex to hypotenuse.
To find:
The value of x.
Solution:
From the given figure, it is clear that the altitude divides the hypotenuse in two segments x and 8.
Length of altitude = 18
If an altitude divide the hypotenuse in 2 segments, then according to the geometric mean theorem, the length of the altitude is the geometric mean of two segments of hypotenuse.
By using geometric mean theorem, we get
Divide both sides by 8.
Therefore, the value of x is 40.5.
Answer:
1335 toys per day.
Step-by-step explanation:
The number of toys produced per day can be modeled by the following function:
In which N(0) is the current number and a is the increase.
A toy company currently produces 950 toys per day. The company plans to increase the number of toys produced per day by 55 each year.
This means that
So
If the company follows through on this plan, how many toys will it be producing per day in 7 years?
This is N(7).
1335 toys per day.
Area=πr^2
find the area then divide by 8
we know that diameter=2radius or diameter/2=radius so
12=diameter
12/2=radius=6
subsitute
area=π(6)^2
area=36π
divide 36π by 8
36π/8=18π/4=9π/2π=4.5π
area of one section is 4.5π square feet or if we aprox pito 3.14159 then we get
4.5(3.14159)=area=14.1372 square feet or 14.14 square feet
Answer:
The answer is B
Step-by-step explanation:
y=5x+2, as the slope is 5x, and the y-intercept is 2
Answer: the function that has the smaller minimum is g(x), and the cordinates are (0,3)
Step-by-step explanation:
We have a function for f(x) and a table for g(x)
first, quadratic functions are symmetrical.
This means that if the minimum/maximum is located at x = x0, we will have that:
f(x0 + A) = f(x0 - A)
For any real value of A.
Then when we look at the table, we can see that:
g(-1) = 7
g(0) = 3
g(1) = 7
then the minimum of g(x) must be at x = 0, and we can see that the minimum value of g(x) is 3.
Now let's analyze f(x).
When we have a quadratic equation of the shape.
y = a*x^2 + b*x + c
the minimum/maximum will be located at:
x = -b/2a
In our function we have:
a = 3
b = 6
then the minimum is at:
X = -6/2*3 = -1
f(-1) = 3*(-1)^2 + 6*-1 + 7 = 3 - 6 + 7 = 3 + 1 = 4
Then the function that has the smaller minimum is g(x), and the cordinates are (0,3)