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Pavlova-9 [17]
2 years ago
7

Find the area of the shaded region

Mathematics
1 answer:
maxonik [38]2 years ago
3 0

Answer:

96 cm^2

Step-by-step explanation:

15 x 10 = 150

9 x 6 = 54

150 - 54 = 96

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In a sports equipment locker, there are 81 balls and 45 baseball mitts. Write the ratio of balls to baseball
Romashka-Z-Leto [24]

Answer: 9:5

Step-by-step explanation:

81:45 I first just divided them both by three and got 27:15 then they were both divisible by 3 so then I got 9:5

6 0
3 years ago
The sector of a circle is shown below. It has a radius of 10 centimeters and a central
disa [49]

Answer:

1) 8.9 cm

2) 44.5 cm^2

Step-by-step explanation:

a) we want to calculate the length of the arc

Mathematically, we use the formula for the length of an arc

That will be ;

theta/360 * 2 * pi * r

theta = central angle = 51

r is radius = 10 cm

so we have ;

51/360 * 2 * 22/7 * 10 = 8.9 cm

2) The area of the sector is;

theta/360 * pi * r^2

51/360 * 22/7 * 10^2

= 44.5 cm^2

5 0
3 years ago
What is the area of this trapezoid? 10cm 5cm 12cm 1.5cm
lutik1710 [3]

Area of a trapezoid = a+b+c x h

10 + 5 +12 = 27 x h

27h = 27 x 1.5 = 40.5

8 0
3 years ago
Madison starts with a population of 1,000 amoebas that triples in size every hour for a number of hours, h. She writes the expre
gtnhenbr [62]

Answer: The meaning of each term of the  Madison’s and Tyler’s expressions is mentioned below.

Step-by-step explanation:

Since, when Madison starts with a population of 1,000 amoebas that triples in size every hour for a number of hours, h.

That is, after 1 hour total number of amoebas = 3×1000 = 3^1\times 1000

After 2 hour,  total number of amoebas = 3×3000=3^2\times 100

After 3 hour, total number of amoebas = 3×9000= 3^3\times 1000

similarly, after h hours, total number of amoebas,

f(h) = 3^h\times 1000

where, 1000 is the initial population of amoeba 3 is the growth factor of population and f(h) is the population of amoeba after h hours.

Since, when Tyler starts with a population of 1 amoeba that  increases 30% in size every hour for a number of hours.

That is, after 1 hour total number of amoebas = (1+0.3)^1

After 2 hour,  total number of amoebas =  (1+0.3)^2

After 3 hour, total number of amoebas =  (1+0.3)^3

Similarly, after h hours, total number of amoebas,

f(h) =(1+0.3)^h

Where,  1 is the initial population of amoeba, 0.3 is the growth rate and 1.3 is the growth factor.


5 0
3 years ago
Read 2 more answers
What is 4x-3(x-2y) +(6x-8y) in standard form
SpyIntel [72]
7x-2y hope this helps
3 0
3 years ago
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