This is a binomial probability situation, since a dog either is adopted or is not adopted. The chances of a dog's being adopted in 0.20. Here we're speaking of 9 visits. Thus, n=9, p=0.20.
One way of doing this problem is to calculate the probability that ONE dog will be adopted, and then that that TWO dogs will be adopted, and so on, up to NINE dogs. Add together these nine probabilities to get your answer.
But a better (faster) approach would be to calculate the probability that ZERO dogs will be adopted, and then to subtract this from 1.000.
Using my TI-84Plus calculator, I figured that P(0 dogs will be adopted) is binompdf(9,0.20,0), or 0.134. Subtracting this from 1.000, we get 0.866 (answer to this problem).
Answer:
Rational and integer i.e option A and C
Hi, I think the answer may be 2.
How I got my answer:
If x equals 18, divide 18 by 3 and you'll get 6, then divide 6 by the other 3 and your quotient should be 2.
Hope I helped!
X= 0 (multiplicity of 1)
X= -2 (multiplicity of 1)
X= 2 (multiplicity of 2)
Answer:
10km+10km*2 = 30km
30km*(1000m/1km) = 30000m
In the second equation of the problem, the kilometers from the initial total distance biked is cancelled out by the conversion of kilometers to meters, as seen in the 1000m/1km (or 1000 meters for every 1 kilometer).
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Step-by-step explanation:
