Let's take a look at D:
<span>D) y = (x-1)^2 - 16 Compare this to
y = (x-h)^2 + k This is the std. equation of a parabola in vertex form.
You can see, by comparison, that h=1 and k= -16; these are the coordinates of the vertex, clearly shown in the diagram.
Since the coefficient of (x-h)^2 is +1, the graph opens upward (which the given graph confirms), and is neither compressed nor stretched vertically.</span>
Answer:
Its either 10 to the power of 6 or ten to the power of 5
Step-by-step explanation:
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Answer:
- f⁻¹(x) = (x + 1) / (x - 2)
- f⁻¹(1 ) = - 2
Step-by-step explanation:
<u>Given function:</u>
- f(x) = (2x + 1) / (x - 1)
<u>Find its inverse, substitute x with y and f(x) with x, solve for y:</u>
- x = (2y + 1) / (y - 1)
- x(y - 1) = 2y + 1
- xy - x = 2y + 1
- xy - 2y = x + 1
- y(x - 2) = x + 1
- y = (x + 1) / (x - 2)
<u>Substitute y with f⁻¹(x):</u>
- f⁻¹(x) = (x + 1) / (x - 2)
<u>Find f⁻¹(1 ):</u>
- f⁻¹(1 ) = ( 1 + 1) / (1 - 2) = 2 / - 1 = - 2
<em><u>Explanation</u></em>:
The only information we have to go on is that ∠AWZ ≅ ∠XYC. However, these are not specific kinds of angles that can prove lines parallel. If we had a pair of alternate interior angles, such as ∠AWZ and ∠WZY, we could say that the lines are parallel. However, we do not have enough information.
Answer:
The sum of the areas of all the surfaces (faces) of a three-dimensional figure.
Step-by-step explanation: