3 years ago

What is the solution to the system of equations?

1 answer:

6 0

When we add the two equations vertically. we get 5x=10 (3x+2x and 4+6, the y's cancel each other out) ∴x=2. Substitute this into any of the equations and we get y=2

so, x=2 and y=2

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almond37 [142]

Answer:

option D

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Step-by-step explanation:

Given in the question an expression,

$\frac{9}{\sqrt{x} -\sqrt{x-3}}$

Step 1

Divide and multiple by $\sqrt{x}+\sqrt{x-3}$ to remove radical sign from denominator.

$\frac{9}{\sqrt{x} -\sqrt{x-3}}*\frac{\sqrt{x} +\sqrt{x-3}}{\sqrt{x} +\sqrt{x-3}}$

Step 2

Apply a² - b² = (a+b)(a-b)

$\frac{9*\sqrt{x}+\sqrt{x-3}}{\sqrt{x^{2}}-\sqrt{(x-3)^{2}}}}$

Step 3

$\frac{9*\sqrt{x}+\sqrt{x-3}}{x-x+3}$

Step 4

$\frac{9*\sqrt{x}+\sqrt{x-3}}{3}$

Step 5

$3*(\sqrt{x}+\sqrt{x-3})$

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