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4 years ago

H=45t-4.9t^2 what's the max height?

1 answer:

const2013 [10]4 years ago

7 0

Differentiate to find time that gradient=0 45-9.8t=0 45=9.8t t =4.59 secs put this value into original equation to get 103.31

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Augie burns 225 calories per 30 minutes of bicycling How many minutes would Augie have to bike to burn 150 calories

lianna [129]

Well first 225/30 is 7.5 so you times 7.5 by any number till you get 150, which the answer is 20 minutes to burn 150 calories

work:
223/30 = 7.5
7.5 * 20 = 150

8 0

3 years ago

Read 2 more answers

Michael will be running a 15 mile road race this weekend how many feet will he run

sergij07 [2.7K]

Answer:

79,200

Step-by-step explanation:

There are 5280 feet in 1 mile, then you just multiply 5280 by the number of miles (15). So 5280 x 15 = 79,200

5 0

3 years ago

Read 2 more answers

Which of the following is the quotient of the rational expressions shown below?

Gre4nikov [31]

Answer:

The answer is D

Step-by-step explanation:

8 0

3 years ago

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Use F = (9/5)C + 32 to convert 100°C to Fahrenheit

pshichka [43]

$\huge\fbox{Answer ☘}$

$\bold\blue{°F = ( \frac{9}{5} )°C \: + 32 }\\\\ °F = ( \frac{9}{5} )100° \: + \: 32 \\\\ °F = 9(20)° + 32 \\\\ °F= 180 + 32 \\\\ \bold{°F = 212°}$

hope helpful~

5 0

3 years ago

What are the solutions to the equation

frosja888 [35]

Answer:

$x_1=\frac{1}{4}+(\frac{\sqrt{7}}{4})i$ and $x_2=\frac{1}{4}-(\frac{\sqrt{7} }{4})i$

Step-by-step explanation:

You have the quadratic function $2x^2-x+1=0$ to find the solutions for this equation we are going to use Bhaskara's Formula.

For the quadratic functions $ax^2+bx+c=0$ with $a\neq 0$ the Bhaskara's Formula is:

$x_1=\frac{-b+\sqrt{b^2-4.a.c} }{2.a}$

$x_2=\frac{-b-\sqrt{b^2-4.a.c} }{2.a}$

It usually has two solutions.

Then we have $2x^2-x+1=0$ where a=2, b=-1 and c=1. Applying the formula:

$x_1=\frac{-b+\sqrt{b^2-4.a.c} }{2.a}\\\\x_1=\frac{-(-1)+\sqrt{(-1)^2-4.2.1} }{2.2}\\\\x_1=\frac{1+\sqrt{1-8} }{4}\\\\x_1=\frac{1+\sqrt{-7} }{4}\\\\x_1=\frac{1+\sqrt{(-1).7} }{4}\\x_1=\frac{1+\sqrt{-1}.\sqrt{7}}{4}$

Observation: $\sqrt{-1}=i$

$x_1=\frac{1+\sqrt{-1}.\sqrt{7}}{4}\\\\x_1=\frac{1+i.\sqrt{7}}{4}\\\\x_1=\frac{1}{4}+(\frac{\sqrt{7}}{4})i$

And,

$x_2=\frac{-b-\sqrt{b^2-4.a.c} }{2.a}\\\\x_2=\frac{-(-1)-\sqrt{(-1)^2-4.2.1} }{2.2}\\\\x_2=\frac{1-i.\sqrt{7} }{4}\\\\x_2=\frac{1}{4}-(\frac{\sqrt{7}}{4})i$

Then the correct answer is option C.

$x_1=\frac{1}{4}+(\frac{\sqrt{7}}{4})i$ and $x_2=\frac{1}{4}-(\frac{\sqrt{7} }{4})i$

3 0

3 years ago