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Eva8 [605]
3 years ago
12

A circular fountain 10 feet in diameter has a circular walk 3 feet wide paved around it.What is the area of the walk?

Mathematics
1 answer:
Over [174]3 years ago
7 0
You have to find the area of the circle first then find the area of the +3. then take the area of first circle and subtract it from the second circle. then you have the area of the sidewalk. your answer would actually be 122.522113ft^2
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Im getting my grade up soo help
Ket [755]
Where is pic…………………,,,,,
4 0
2 years ago
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Please help me out with this
Ivanshal [37]

Answer:

374.1

Step-by-step explanation:

Area of Hexagon = \frac{3\sqrt{3} }{2} * a^{2}

The ' a ' is the side length.

So now we just plug in the values

\frac{3\sqrt{3} }{2} *12^{2} = 374.12

3 0
3 years ago
How do i solve this question
frozen [14]
\bf \begin{cases}
h(x)=(f\circ g)(x)\\
h(x)=\sqrt{x+5}\\
f(x)=\sqrt{x+2}
\end{cases}\\\\
-------------------------------\\\\
(f\circ g)(x)\implies f[\ g(x)\ ]\implies f[\ g(x)\ ]=\sqrt{g(x)+2}\qquad thus
\\\\\\
\sqrt{g(x)+2}=(f\circ g)(x)=h(x)=\sqrt{x+5}\qquad therefore
\\\\\\
\sqrt{g(x)+2}=\sqrt{x+5}\impliedby \textit{squaring both sides}\\\\\\
g(x)+2=x+5\implies g(x)=x+5-2\implies \boxed{g(x)=x+3}
8 0
3 years ago
Help me with this I need help asap!
GuDViN [60]

Answer:

29.5

Step-by-step explanation:

UV=\frac{27+32}{2} \\ \\ UV=29.5

3 0
2 years ago
Find h(2/3) if h(x) = 6x <br><br> 2 4 6 8
arlik [135]
H(x) = 6x     

it gives you what x is so plug that in the equation to find it.

h(2/3) = 6(2/3)
h(2/3) = 6 × 2 ÷ 3
h(2/3) = 12 ÷ 3
h(2/3) = 4

so your answer is 4.

hope this helps, God bless!
7 0
3 years ago
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