Question

Not really sure how to do this one (ignore writing above)

Answer 1

$\bf \left( x^{4a-3} \right)^2=x^{10}\implies x^{(4a-3)2}=x^{10} \\\\\\ \textit{since the bases are the same, the exponents must also be the same} \\\\\\ 2(4a-3)=10\implies 4a-3=\cfrac{10}{2}\implies 4a-3=5\implies 4a=8 \\\\\\ a=\cfrac{8}{4}\implies \boxed{a=2}$