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Tpy6a [65]
3 years ago
13

Simplify each expression by combining like terms. 3n - 1 + 8n +5

Mathematics
1 answer:
Kay [80]3 years ago
3 0

Answer:

3n-1+8n+5

3n+8n-1+5

11n+4

Let me know if this helps!

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Gragh h(t) = 400 − 39t − 157e−t/4
Paraphin [41]
The graph of h(t) = 400 - 39t - 157e^{ \frac{t}{4} } is attached.

3 0
3 years ago
The 5th of 9 consecutive whole numbers whose sum is 153 is?
sergejj [24]

We can start this problem by finding out what the lowest consecutive number's value is (x). Since consecutive numbers are numbers that are 1 apart from each other, the sum of 9 consecutive numbers would look like


x + (x+1) + (x+2) + (x+3) + (x+4) + (x+5) + (x+6) + (x+7) + (x+8)


Since we know that they equal 153,


x + (x+1) + (x+2) + (x+3) + (x+4) + (x+5) + (x+6) + (x+7) + (x+8) = 153


Now we combine like terms


9x + 36 = 153


Simplify


9x = 117


x = 13


Now, we need to find what the 5th consecutive number is equal to. The fifth consecutive number is (x+4), so 13 + 4 is 17, meaning that the 5th of 9 consecutive numbers that add up to 153 is 17.

4 0
3 years ago
Read 2 more answers
What expression is equivalent to 2x+3y-x-(8+1)
Paha777 [63]

Answer:

Step-by-step explanation:

2x + 3y - x - 9

x + 3y - 9

3 0
3 years ago
In a certain community, 36 percent of the families own a dog and 22 percent of the families that own a dog also own a cat. In ad
zysi [14]

Answer:  a) 0.0792   b) 0.264

Step-by-step explanation:

Let Event D = Families own a dog .

Event C = families own a cat .

Given : Probability that families own a dog : P(D)=0.36

Probability that families own a dog also own a cat : P(C|D)=0.22

Probability that families own a cat : P(C)= 0.30

a) Formula to find conditional probability :

P(B|A)=\dfrac{P(A\cap B)}{P(A)}\\\\\Rightarrow P(A\cap B)=P(B|A)\times P(A)   (1)

Similarly ,

P(C\cap D)=P(C|D)\times P(D)\\\\=0.22\times0.36=0.0792

Hence, the probability that a randomly selected family owns both a dog and a cat : 0.0792

b) Again, using (2)

P(D|C)=\dfrac{P(C\cap D)}{P(C)}\\\\=\dfrac{0.0792}{0.30}=0.264

Hence, the conditional probability that a randomly selected family owns a dog given that it owns a cat = 0.264

5 0
3 years ago
An algebraic equation is an equation that includes:
MrRissso [65]

Answer:

ç

Step-by-step explanation:

fufujphgfhjunkksbkbbdkdbkdldbdjdbdkdjjdkdmdljdbdivdjbdkd

5 0
3 years ago
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