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anastassius [24]
3 years ago
9

What is -2y to the third power when y=-5

Mathematics
1 answer:
MA_775_DIABLO [31]3 years ago
3 0
250, when plugged in, -5 becomes -125, then multiplied by -2 is 250
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Tatiana [17]
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7 0
3 years ago
yesterday , Elsa had K baseball cards today she gave 12 away ,using K write an expression for the number of cards elsa has left
Molodets [167]

Answer:

K - 12 = X

Step-by-step explanation:

Can't really, it's an expression.

4 0
3 years ago
Read 2 more answers
Please help me!!!!!!!!:(
horsena [70]

Answer:

24% chance

Step-by-step explanation:

First, find the total number of graduates in the table, that number is 2610, that will be your numerator.

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Now divide the smaller number/numerator (2610) by the larger number/denominator (10730)

\frac{2610}{10730} = 0.2432432...

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Now, round to the nearest percentage: 24%


7 0
3 years ago
Solve v+8<3 or -8v-40 .
Setler79 [48]
The answer is:

v < -5 or v > 5

Hope this helps ✨❤️
6 0
2 years ago
If f(1) = 0, what are all the roots of the function f(x)=x^3+3x^2-x-3? Use the Remainder Theorem.
Sophie [7]
There's no if about it, 

f(x)=x^3+3x^2-x-3&#10;

has a zero f(1)=0 so x-1 is a factor.   That's the special case of the Remainder Theorem; since f(1)=0 we'll get a remainder of zero when we divide f(x) by x-1.

At this point we can just divide or we can try more little numbers in the function.  It doesn't take too long to discover f(-1)=0 too, so  x+1 is a factor too by the remainder theorem.  I can find the third zero as well; but let's say that's out of range for most folks.

So far we have 

x^3+3x^2-x-3 = (x-1)(x+1)(x-r)

where r is the zero we haven't guessed yet.  Again we could divide f(x) by (x-1)(x+1)=x^2-1 but just looking at the constant term we must have

-3 = -1 (1)(-r) = r

so

x^3+3x^2-x-3 = (x-1)(x+1)(x+3)

We check f(-3)=(-3)^3+3(-3)^2 -(-3)-3 = 0 \quad\checkmark

We usually talk about the zeros of a function and the roots of an equation; here we have a function f(x) whose zeros are

x=1, x=-1, x=-3

8 0
3 years ago
Read 2 more answers
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