Answer:
5 hamburger packages and 6 bun packages
Step-by-step explanation:
It is asking for the highest common multiple of 12 and 10. the first time a multiple of 12 is divisible by 10 is at 12x5, which is 60. now divide 60 by 12 and 10, 5 and 6.
Aruthmetic sequene is
an=a1+(n-1)d
where d=common difference between terms
adds 6 every time
d=6
first term is 8
a1=8
8+6(n-1)
distribute
8+6n-6
8-6+6n
2+6n is answer
You have to start by using the distributive property. So you take the number next to the parentheses which is “8” and you multiply it with “2x”. This gives you “16x”. Then you multiply “8” with “3” and that gives you “24”. You now have the equation “16x + 24 = 48”.
The next step is to subtract “24” with “48”. This leaves you with “24”. Then you now have “16x = 24” as your new equation. The last step is to divide “16x” with “16”, this cancels it out with itself. Then you divide “24” with “16” and you get 1.5. So “X” equals 1.5 or you can convert it into a fraction witch gives you “3/4”.
Answer:
78 novels
Step-by-step explanation:
N= novels
M= month
6N = 1M
? = 13M
6N × 13M= 78NM
78NM ÷ 1M
cancel M, therefore;
the number of novels Usama needs to read in 13 months is 78.
The difference between consecutive integers is 1.
Let x = smaller integer.
Then x + 1 is the next greater consecutive integer.
x(x + 1) = 132
x^2 + x - 132 = 0
(x + 12)(x - 11) = 0
x + 12 = 0 or x + 11 = 0
x = -12 or x = -11
Since x is the smaller of the two integers, the answers are:
-12, -11
11, 12
There are two pairs of such integers.
