What is the value of x in the given circle? please help!!!!

What is the y-intercept of the function f(x) = _2/9×+1/3

Leokris [45]

Answer:The y intercept is (0.0.333)

Step-by-step explanation:

5 0

2 years ago

Which is not Equivalent to 3:5 A.30:50 B.21:28 C:15:28 D.9:15

kirza4 [7]

Answer:

B.

Step-by-step explanation:

Since 21 is divided by 3 you might think that it is equivalent but remeber you have to divide by both sides, so if you divide 21 by 7 it works but 28 by seven does not! Hope this helps!

3 0

2 years ago

A data set with a mean of 34 and a standard deviation of 2.5 is normally distributed

tresset_1 [31]

Answer:

a) $z= \frac{34-34}{2.5}= 0$

$z= \frac{39-34}{2.5}= 2$

And we want the probability from 0 to two deviations above the mean and we got 95/2 = 47.5 %

b) $P(X$

$z= \frac{31.5-34}{2.5}= -1$

So one deviation below the mean we have: (100-68)/2 = 16%

c) $z= \frac{29-34}{2.5}= -2$

$z= \frac{36.5-34}{2.5}= 1$

For this case below 2 deviation from the mean we have 2.5% and above 1 deviation from the mean we got 16% and then the percentage between -2 and 1 deviation above the mean we got: (100-16-2.5)% = 81.5%

Step-by-step explanation:

For this case we have a random variable with the following parameters:

$X \sim N(\mu = 34, \sigma=2.5)$

From the empirical rule we know that within one deviation from the mean we have 68% of the values, within two deviations we have 95% and within 3 deviations we have 99.7% of the data.

We want to find the following probability:

$P(34 < X$

We can find the number of deviation from the mean with the z score formula:

$z= \frac{X -\mu}{\sigma}$

And replacing we got

$z= \frac{34-34}{2.5}= 0$

$z= \frac{39-34}{2.5}= 2$

And we want the probability from 0 to two deviations above the mean and we got 95/2 = 47.5 %

For the second case:

$P(X$

$z= \frac{31.5-34}{2.5}= -1$

So one deviation below the mean we have: (100-68)/2 = 16%

For the third case:

$P(29 < X$

And replacing we got:

$z= \frac{29-34}{2.5}= -2$

$z= \frac{36.5-34}{2.5}= 1$

For this case below 2 deviation from the mean we have 2.5% and above 1 deviation from the mean we got 16% and then the percentage between -2 and 1 deviation above the mean we got: (100-16-2.5)% = 81.5%

7 0

2 years ago

John leaves school to go home.his bus drives 6 kilometers north and then goes 7 kilometers west.how far is John's house from the

otez555 [7]

Answer:

John is 9.21 km form the school.

Step-by-step explanation:

John leaves school to go home. His bus drives 6 kilometres north and then goes 7 kilometres west. It is required to find John's distance from the school. It is equal to the shortest path covered or its displacement. So,

$d=\sqrt{6^2+7^2} \\\\d=9.21\ km$

So, John is 9.21 km form the school.

5 0

3 years ago

1+4=5 2+5=12 3+6=21 8+11 =

alekssr [168]

The answer to 8+11 is 19 because 8+1 is 9 so 11+8 is 19

4 0

3 years ago

Read 2 more answers