Question

Let AB be the directed line segment beginning at point A(2,3) and ending at point B(6,8). Find the point P on the line segment that partitions the line segment into the segments AP and PB at a ratio of 4:3.

Answer 1

Answer:

Step-by-step explanation:

A(2,3) and B(6,8)

AP:PB=4:3

$x=\frac{m x_{2}+nx_{1}}{m+n} =\frac{4 \times 6+3 \times 2}{4+3} =\frac{30}{7} \\y=\frac{my_{2}+ny_{1}}{m+n} =\frac{4 \times 8+3 \times 3}{4+3}=\frac{41}{7}\\so~P~is~(\frac{30}{7},\frac{41}{7})$