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PolarNik [594]
3 years ago
10

54.85 rounded to the nearest 1/10th percent

Mathematics
1 answer:
Iteru [2.4K]3 years ago
8 0

Answer:

54.9

Step-by-step explanation:

You always round up if its 0.5 or anything .5

54.58 broken down:

The 5 is the Tens place

The 4 is the Ones place

The 8 is the Tenth place (what the question is asking for)

The 5 is the Hundredths place.

:)  Hope this helps! Please mark brainliest! :)

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Can someone solve this?
ladessa [460]
  • First question:

Recall that \cos^2x+\sin^2x=1 and \sqrt{x^2}=|x| for all x. So

\sqrt{1-\cos^2x}=\sqrt{\sin^2x}=|\sin x|

\sqrt{1-\sin^2x}=\sqrt{\cos^2x}=|\cos x|

For 0, we expect both \cos x>0 and \sin x>0 (i.e. the sine and cosine of any angle that lies in the first quadrant must be positive). By definition of absolute value, |x|=x if x>0.

So we have

\dfrac{\sqrt{1-\cos^2x}}{\sin x}+\dfrac{\sqrt{1-\sin^2x}}{\cos x}=\dfrac{\sin x}{\sin x}+\dfrac{\cos x}{\cos x}=1+1=\boxed{2}

making H the answer.

  • Second question:

C is always true, because the inequality reduces to x > y.

6 0
3 years ago
Claire has $18. She wants to buy a book and magazine. The book costs $13.28. How much can Claire spend on a magazine?
dedylja [7]
Claire can spend $4.72 on a magazine
7 0
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What is the answer to <br> 1+38*225(12/77)
Neporo4naja [7]
1+38*225(12/77)
1+38*225*6.41
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Use pemdas to solve it
4 0
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Read 2 more answers
Consider two boxes, one containing one black and one white marble, the other, two black and one white marble. A box is selected
valina [46]

Answer:

\frac{7}{12}

Step-by-step explanation:

Probability refers to chance of happening of some event.

Conditional probability is the probability of an event A, given that another event B has already occurred.

B_1,B_2 denote the two boxes.

In box B_1:

No. of black balls = 1

No. of white balls = 1

In box B_2:

No. of black balls = 2

No. of white balls = 1

Let B, W denote black and white marble.

So, probability that either of the boxes B_1,B_2 is chosen is \frac{1}{2}

Probability that a black ball is chosen from box B_1 = \frac{1}{2}

Probability that a black ball is chosen from box B_2=\frac{2}{3}

To find:probability that the marble is black

Solution:

Probability that the marble is black = \frac{1}{2}(\frac{1}{2} )+\frac{1}{2}(\frac{2}{3})=\frac{1}{4}+\frac{1}{3}=\frac{7}{12}

6 0
3 years ago
Find the quotient. n^4/n^5
zhenek [66]
Reduce the expression by cancelling the common factors: 1/n
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