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tester [92]
3 years ago
14

I’ll give Brainly! Match each problem with the answer!

Mathematics
2 answers:
yan [13]3 years ago
8 0
89+43-10=122
100x2 divided by 5=40
100 divided by 2 x5=250
15+8-6=17
4x8-14=18
natita [175]3 years ago
7 0
18: 4 x 8 - 14
17: 15 + 8 -6
40: 100 x 2 / 5
250: 100 / 2 x 5
122: 89 + 43 - 10
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If a fair coin is flipped 15 times, what is the probability that there are more heads than tails?
ludmilkaskok [199]

Answer:

The probability that there are more heads than tails is equal to \dfrac{1}{2}.

Step-by-step explanation:

Since the number of flips is an odd number, there can't be an equal number of heads and tails. In other words, there are either

  • more tails than heads, or,
  • more heads than tails.

Let the event that there are more heads than tails be A. \lnot A (i.e., not A) denotes that there are more tails than heads. Either one of these two cases must happen. As a result, P(A) + P(\lnot A) = 1.

Additionally, since this coin is fair, the probability of getting a head is equal to the probability of getting a tail on each toss. That implies that (for example)

  • the probability of getting 7 heads out of 15 tosses will be the same as
  • the probability of getting 7 tails out of 15 tosses.

Due to this symmetry,

  • the probability of getting more heads than tails (A is true) is equal to
  • the probability of getting more tails than heads (A is not true.)

In other words P(A) = P(\lnot A).

Combining the two equations:

\left\{\begin{aligned}&P(A) + P(\lnot A) = 1 \cr &P(A) = P(\lnot A)\end{aligned}\right.,

P(A) = P(\lnot A) = \dfrac{1}{2}.

In other words, the probability that there are more heads than tails is equal to \dfrac{1}{2}.

This conclusion can be verified using the cumulative probability function for binomial distributions with \dfrac{1}{2} as the probability of success.

\begin{aligned}P(A) =& P(n \ge 8) \cr =& \sum \limits_{i = 8}^{15} {15 \choose i} (0.5)^{i} (0.5)^{15 - i}\cr =& \sum \limits_{i = 8}^{15} {15 \choose i} (0.5)^{15}\cr =& (0.5)^{15} \left({15 \choose 8} + {15 \choose 9} + \cdots + {15 \choose 15}\right) \cr =& (0.5)^{15} \left({15 \choose (15 - 8)} + {15 \choose (15 - 9)} + \cdots + {15 \choose (15 - 15)} \right) \cr =& (0.5)^{15} \left({15 \choose 7} + {15 \choose 6} + \cdots + {15 \choose 0}\right)\end{aligned}

\begin{aligned}\phantom{P(A)} =& \sum \limits_{i = 0}^{7} {15 \choose i} (0.5)^{15}\cr =& P(n \le 7) \cr =& P(\lnot A)\end{aligned}.

6 0
3 years ago
PLSSS HELP (What are the square roots of 121?)
Orlov [11]

Answer:

11

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Slope Quiz<br> ...........................................................
finlep [7]

Answer:

I hope it helps you the answer is 10/9

3 0
2 years ago
10. 10. If AB bisects CAF, and m&lt;EAF = 72°,<br>then the m&lt;BAF =​
never [62]

The measure of ∠BAF is 54°.

Solution:

DF and CE are intersecting lines.

m∠EAF = 72° and AB bisects ∠CAF.

∠EAF and ∠DAC are vertically opposite angles.

Vertical angle theorem:

<em>If two lines are intersecting, then vertically opposite angles are congruent.</em>

∠DAC ≅ ∠EAF

m∠DAC = 72°

<em>Sum of the adjacent angles in a straight line = 180°</em>

m∠DAE + m∠EAF = 180°

m∠DAE + 72° = 180°

Subtract 72° from both sides.

m∠DAE = 108°

∠CAF and ∠DAE are vertically opposite angles.

⇒ m∠CAF = m∠DAE

⇒ m∠CAF = 108°

AB bisects ∠CAF means ∠CAB = ∠BAF

m∠CAB + m∠BAF = 108°

m∠BAF + m∠BAF = 108°

2 m∠BAF = 108°

Divide by 2 on both sides, we get

m∠BAF = 54°

Hence the measure of ∠BAF is 54°.

4 0
3 years ago
Y = 2/3 when x = 0.2
azamat
Please explain some more:)
4 0
3 years ago
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