Answer:
The probability that there are more heads than tails is equal to
.
Step-by-step explanation:
Since the number of flips is an odd number, there can't be an equal number of heads and tails. In other words, there are either
- more tails than heads, or,
- more heads than tails.
Let the event that there are more heads than tails be
.
(i.e., not A) denotes that there are more tails than heads. Either one of these two cases must happen. As a result,
.
Additionally, since this coin is fair, the probability of getting a head is equal to the probability of getting a tail on each toss. That implies that (for example)
- the probability of getting 7 heads out of 15 tosses will be the same as
- the probability of getting 7 tails out of 15 tosses.
Due to this symmetry,
- the probability of getting more heads than tails (A is true) is equal to
- the probability of getting more tails than heads (A is not true.)
In other words
.
Combining the two equations:
,
.
In other words, the probability that there are more heads than tails is equal to
.
This conclusion can be verified using the cumulative probability function for binomial distributions with
as the probability of success.

.
Answer:
11
Step-by-step explanation:
Answer:
I hope it helps you the answer is 10/9
The measure of ∠BAF is 54°.
Solution:
DF and CE are intersecting lines.
m∠EAF = 72° and AB bisects ∠CAF.
∠EAF and ∠DAC are vertically opposite angles.
Vertical angle theorem:
<em>If two lines are intersecting, then vertically opposite angles are congruent.</em>
∠DAC ≅ ∠EAF
m∠DAC = 72°
<em>Sum of the adjacent angles in a straight line = 180°</em>
m∠DAE + m∠EAF = 180°
m∠DAE + 72° = 180°
Subtract 72° from both sides.
m∠DAE = 108°
∠CAF and ∠DAE are vertically opposite angles.
⇒ m∠CAF = m∠DAE
⇒ m∠CAF = 108°
AB bisects ∠CAF means ∠CAB = ∠BAF
m∠CAB + m∠BAF = 108°
m∠BAF + m∠BAF = 108°
2 m∠BAF = 108°
Divide by 2 on both sides, we get
m∠BAF = 54°
Hence the measure of ∠BAF is 54°.
Please explain some more:)