A(b-c)=ab-ac
(1/7)(1/3h-1/2)=(1/7)(1/3h)-(1/7)(1/2)=1/21h-1/14
now we gots
6 and 1/7+1/21h-1/14
rearange
6 and 1/7-1/14+1/21h
make common denom which is 14
6 and 2/14-1/14+1/21h
6 and 1/14+1/21h
Answer:
76°
Step-by-step explanation:
The opposite angles of a parallelogram are equal, so if one angle is 76°, then the opposite angle will be the same.
I hope this helps!
Answer:
81.86%
Step-by-step explanation:
We have been given that final exam scores are normally distributed with a mean of 74 and a standard deviation of 6.
First of all we will find z-score using z-score formula.
Now let us find z-score for 86.
Now we will find P(-1<Z) which is probability that a random score would be greater than 68. We will find P(2>Z) which is probability that a random score would be less than 86.
Using normal distribution table we will get,

We will use formula
to find the probability to find that a normal variable lies between two values.
Upon substituting our given values in above formula we will get,


Upon converting 0.81859 to percentage we will get

Therefore, 81.86% of final exam score will be between 68 and 86.
The answer for this is hundredth because it is .01 (two values behind decimal means hundredths)