solution:
I choose 5 women from a pool of 10 in 10C2 ways.
I choose 5 men from a pool of 12 in 12C2 ways.
So total number of ways of choosing in 10C2 x 12C2. Now I need to arrange them in 5 pairs. This is where I have a different solution. The solution says that there are 5! ways to arrange them in pairs.
But I cant seem to understand why? My reasoning is that for first pair position I need to choose 1 man from 5 and 1 woman from 5. So for the first position I have 5 x 5 choices (5 for man and 5 for woman). Similarly for the second position I have 4 x 4 choices and so on. Hence the total ways are 5! x 5!
So I calculate the total ways as 10C2 * 12C2 * 5! * 5!. Can anyone point the flaw in my reasoning for arranging the chosen men and women in pairs.
It went from 10 to -2, so you need to find the difference. The way you'd do this is: 10 - (-2). Do you know how to subtract a negative number from a positive number?
Answer:

Step-by-step explanation:
we know that


Let
x ------> new battery life
The equation that represent this situation is

convert to mixed number

Answer:
b = 7, c = -44
Step-by-step explanation:
If the quadratic equation has the solutions -11 and 4, the two factors are:

Since when we use the zero factor property we get
x+11=0 ⇒ x= -11
x-4=0 ⇒ x=4
Thus, we have used the zero factor property in reverse to find the factorization of the quadratic equation.
Now we develop the multiplications between parenthesis:

So b is the number that accompanies the x: b = 7
and c is the independent number: c = -44
Ok
in a 30-60-90 right triangle, if the leg oposite the 30 degree angle is x then the hypontuse is 2x
if the leg oposite the 30 degree angle is 12 inches then the hypontuse is 12*2 or 24 inches