Answer:
<h2>A. (0,1)</h2>
Step-by-step explanation:
The question lacks the e=required option. Find the complete question below with options.
Which of the following points does not belong to the quadratic function
f(x) = 1-x²?
a.(0,1) b.(1,0) c.(-1,0)
Let f(x) = 0
The equation becomes 1-x² = 0
Solving 1-x² = 0 for x;
subtract 1 from both sides;
1-x²-1 = 0-1
-x² = -1
multiply both sides by minus sign
-(-x²) = -(-1)
x² = 1
take square root of both sides;
√x² = ±√1
x = ±1
x = 1 and x = -1
when x = 1
f(x) = y = 1-1²
y = 1-1
y = 0
when x = -1
f(x) = y = 1-(-1)²
y = 1-1
y = 0
Hence the coordinate of the function f(x) = 1-x² are (±1, 0) i.e (1, 0) and (-1, 0). The point that does not belong to the quadratic function is (0, 1)
The answer to the question is 1 and 3/4
Answer:
The 500 mice would be the carrying capacity of the field being studied.
Step-by-step explanation:
For the first year of study, the mouse population demonstrates exponential growth.
But by third year, the mouse population has stabilized at approximately 500 mice.
Thus, this 500 mice would be the carrying capacity of the field being studied.
Carrying capacity is defined as the measure to demonstrate the maximum population size that any given environment can sustain for an unspecified time period.
We know that
[length of a circle]=2*pi*r
r=12 in
[length of a circle]=2*pi*12--------------> 24pi in
if 360° (full circle)--------------------> has a length of 24pi in
X-------------------------------------------> 8pi
X=8pi*360/24pi-----------> 120°
the answer is 120°
Answer:
7
Step-by-step explanation:
7^2 =49
49 -21 =28
28÷7 = 4
